Answer:
The longer part is <u>45 cm</u> long and the shorter part is <u>25 cm</u> long.
Step-by-step explanation:
Given:
A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part.
Now, to find the length of each part of the stick.
Let the shorter part be 
So, the longer part is 
Total length of the stick = 70 cm.
Now, to get the length of each part we solve an equation:
<em>The length of the shorter part is 25 cm.</em>
Now, substituting the value of 
:
<em>The length of longer part is 45 cm.</em>
Therefore, the longer part is 45 cm long and the shorter part is 25 cm long.
Answer:
Never gonna
Step-by-step explanation:
give you up,
Let you down,
make you cry
Run around and desert you
Answer:
30°, 30° and 120°
Step-by-step explanation:
Using the information given in the question.
let x be the measure of each congruent base angle , then
the third angle = 3x + 30
Sum the 3 angles and equate to 180
3x + 30 + x + x = 180, that is
5x + 30 = 180 ( subtract 30 from both sides )
5x = 150 ( divide both sides by 5 )
x = 30
Thus
The 2 congruent bas angles are each = 30°
The third angle = 3x + 30 = 3(30) + 30 = 90 + 30 = 120°
Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people = 
Standard deviation of 50 people 
Then , the probability its maximum safe load will be exceeded =
![P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855](https://tex.z-dn.net/?f=P%28X%3E10000%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B10000-9500%7D%7B282.84%7D%29%5C%5C%5C%5C%3DP%28z%3E1.7671-8%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.7678%29%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3DP%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.96145%5C%20%5C%20%5C%20%5B%5Ctext%7B%20By%20p-value%20of%20table%7D%5D%5C%5C%5C%5C%3D0.03855)
Thus , the probability its maximum safe load will be exceeded = 0.03855
