Answer:
Volume = 722.1 L
Explanation:
Given data:
Mass of gas = 902.0 g
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Volume of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of C₂H₄.
Number of moles = mass/molar mass
Number of moles = 902.0 g/ 28.05 g/mol
Number of moles = 32.2 mol
Volume of gas:
PV = nRT
1 atm ×V = 32.2 mol × 0.0821 atm.L/ mol.K × 273.15 K
V = 722.1 atm.L/1 atm
V = 722.1 L
Answer: D the average mass of all the isotopes
Explanation:
When an alpha particle is released by an atom, the atom loses a helium nucleus.
Zinc
Explanation:
Electron configuration:
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s²
To decipher this atom, we must understand what each of the letters and number represents;
1s²
1 is the principal quantum number
s is the azimuthal number or the subshell
2 superscript is the number of electrons
Using the number of electrons, we can deduced the atom:
2+2+6+2+6+10+2 = 30 electrons
The element with 30 electrons on the periodic table is Zinc
Learn more:
Periodic table brainly.com/question/1704778
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Answer:
B. Q > K precipitate will form
Explanation:
The reaction is;
Ba(NO3)2(aq) + Na2CO3(aq) ------> BaCO3(s) + 2NaNO3(aq)
Hence the reaction could form a precipitate of BaCO3.
Number of moles of carbonate ions = 50/1000 * 0.10 M = 5 * 10^-3 moles
Number of moles of Barium ions = 20/1000 * 0.10 M = 2 * 10^-3 moles
Total volume after reaction = 20ml + 50ml = 70 ml or 0.07 L
Molarity Barium ions = 5 * 10^-3 moles/ 0.07 L = 0.07 M
Molarity carbonate ions = 2 * 10^-3 moles/ 0.07 L =0.03 M
Q = [Ba^2+] [CO3^2-] = 0.07 * 0.03 = 2.1 * 10^-3
But K = 2.58 × 10
^−
9
We can clearly see that Q>K therefore precipitate will form