<span>64.94
First, write out an expression about what we know
0.6915 * 62.93 + 0.3085 * x = 63.55
Now solve for x
0.6915 * 62.93 + 0.3085 * x = 63.55
43.5161 + 0.3085 * x = 63.55
0.3085 * x = 20.03391
x = 64.93972
Rounding the answer to 2 decimal places gives x = 64.94</span>
I’m just here for the points sorry
Answer:
The awnser is A.
Explanation:
I got it right on edgenuity. If im wrong sorry ;-;
Answer:
0.2193 μm
Explanation:
The reaction showing the Photodissociation of ozone (O3) is given below as:
O₃ + hv --------------------------> O₂ + O⁺
H° (142.9) (0) (438kJ/mol).
The first thing to do here is to determine the change in the enthalpy of the total reaction, this can be done by subtracting the change in the enthalpy of the reactant from the change in enthalpy in the product. Hence, we have:
ΔH° = [438 kJ/mol + 247.5 kJ/mol] - (142.9) = 542.6 KJ/mol.
This value, that is 542.6 KJ/mol will then be used in the determination of the value for the maximum wavelength that could cause this photodissociation.
Therefore, the maximum wavelength could cause this photodissociation ≤ h × c/ E = [ 1.199 × 10⁻⁴]/ 542.6 = 2.193 × 10⁻⁷ = 0.2193 μm
State functions include density, internal energy, enthalpy, entropy. Such a relation cannot be written for path functions, especially since these cannot be defined for the limiting states. Path functions depend on the route taken between two states. Two examples of path functions are heat and work.
