Answer:
Explanation:
The hydrosphere represents the total amount of water on earth. Soil water is part of the hydrosphere.
The lithosphere represents the varieties of rocks present on the planet, including their weathered part which is the soil.
The atmosphere represents the different gas layers surrounding the earth.
The biosphere represents the portion of the earth that supports life.
<em>When soil water moves into the tree through the roots of the tree, the hydrosphere, the lithosphere and the biosphere are interacting all together. When the some of the water taken in is released to the atmosphere as vapor through evapotranspiration, it represents an interaction with the atmosphere.</em>
Answer:
g= 9.81m/s..................
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
Answer: 160 m
Explanation: First find time or t using the formula for acceleration:
a = vf - vi / t
So t is equal to:
t = vf - vi / a
= 0 m/s - 20 m/s / -2.5 m/s²
= 8 s
To find the distance use the formula for velocity:
v = d / t
Derive for d:
d = v x t
= 20 m/s x 8 s
= 160 m
