To solve this problem we will apply the concept related to the electric field. The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

$E = \frac{kV}{r^2}$

Here,

k = Coulomb's constant

V = Voltage

r = Distance

Replacing we have

$E = \frac{(9*10^9)(2*10^{-6})}{((10+5)*10^{-2})^2}$

$E = 8*10^5N/C$

Therefore the magnitude of the electric field is $8*10^5N/C$

4 0

3 years ago

A sample of oxygen gas with a volume of 3.0 m3 is at 100 C. The gas is heated so that

vesna_86 [32]

$\qquad\qquad\huge\underline{{\sf Answer}}$

According to Charles law, if pressure remains constant, volume varies directly with temperature. so we can infer that :

$\qquad\sf{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}$

So, we can use this formula to find out the final temperature of the gas ~

Note : Take temperature in Kelvin ( 100°C = 373 K )

$\qquad \sf \dashrightarrow \: \dfrac{3}{373} = \dfrac{6}{x}$

$\qquad \sf \dashrightarrow \: x = \dfrac{6}{3} \times 373$

$\qquad \sf \dashrightarrow \: x = 2 \times 373$

$\qquad \sf \dashrightarrow \: x =74 6 \: K$

Now, convert it to Celsius ~

i.e 746 - 273 = 473° C

So, the final temperature of the gas will be equal to 473° C

6 0

2 years ago

Does the resistance of an object depend on the path current takes through it? Consider, for example, a rectangular bar—is its re

SVETLANKA909090 [29]

Answer:

Explanation:

An object's resistance depends on its form and the substance it is made from. The electrical resistance R of the cylinder, as you might expect, is directly proportional to its length L, similar to a pipe's resistance to fluid flow. The longer the cylinder, the more charges of collisions with its atoms can occur. The bigger the cylinder diameter, the more current it can carry.

8 0

4 years ago