If the mass of an object is 5 kg and the velocity is 8 m/s, what is the momentum?

A cylinder is filled with 10.0 L of gas and a piston is put into it. The initial pressure of the gas is measured to be 163. kPa.

alexgriva [62]

Answer:

P₂ = 370 kPa

Explanation:

Boyle's law: States that the volume of a given mass of gas is inversely proportional to its pressure provided the temperature remains constant. It can be expressed mathematically as,

P₁V₁ = P₂V₂................ Equation 1

Where P₁ = Initial Pressure, V₁ = Initial volume, P₂ = Final Pressure, V₂ = Final Volume.

Making P₂ The subject of the equation above,

P₂ = P₁V₁/V₂..................... equation 2

Substituting these vaues into equation 2,

Where P₁ = 163 kPa = 163000 pa, V₁ = 10 L, V₂ = 4.4 L.

P₂ = 163000(10)/4.4

P₂ = 370454.55 Pa

P₂ = 370000 Pa

P₂ = 370 kPa To 3 significant figure.

Therefore Final pressure = 370 kPa

6 0

3 years ago

Can someone answer these?

natita [175]

Short Answer

3: C

4: D

Problem Three

Remark

Somewhere we ought to be told that this is the Doppler Effect. I have never done a problem using this formula, so I think I'm doing it correctly, but no guarantees. My guess is that the frequency increases as it comes towards you and decreases as it moves away from you. I think that is correct.

Formula

Givens

f' = observed frequency
f = actual frequency
v = velocity of sound or light waves.
vo = velocity of observer (in both cases 0)
vs = velocity of source.

f' = (v + vo) * f / (v - vs)

Solution

v = 3*10^8 m/s
f' = 1.1 f
f = f
vo = 0 We are standing still while all this is going on.
vs = ???

f'/f = 1.1

1.1 = (3*10^8 + 0 ) / (3*10^8 - vs)

3.3*10^8 - 1.1*vs = 3*10^8

3.3*10^8 - 3*10^8= 1.1 vs

0.3 * 10^8 = 1.1 vs

2.73 * 10^7 = vs

The closest answer is 3.00 * 10^7 which is C

Problem Four

Here what is happening is that you are looking for the frequency resulting from a wave moving towards you at 1/2 the speed of sound. You are not moving.

Givens

v = v
vs = 1/2 v
f ' = ?
f = 1000 hz
vo =0

f' = v/(v - 1/2v) * 1000

f' = v/ (1/2 v) * 1000

f' = 2 * 1000

f' = 2000 which is D

4 0

4 years ago

4. A car of mass 2000 kg is traveling at 45 m/s when the driver spots a policeman anead. i ne univer apprivo

MariettaO [177]

Answer:

The change in the Kinetic Energy of the car, E = 1449000 joules

Explanation:

Given,

The mass of the car, m = 2000 Kg

The speed of the car, v = 45 m/s

The brake applied on the car for a duration, t = 3 s

The average force applied by the brake, F = 1.4 x 10⁴ N

The kinetic energy of the body is given by the relation,

K.E = 1/2 mv²

The initial kinetic energy of the car,

K.E = 0.5 x 2000 x 45

= 2025000 J

The force applied by the brakes

F = m x a

Therefore, the deceleration of the car

a = F / m

= 1.4 x 10⁴ / 2000

= 7 m/s²

Using the first equations of motion,

v = u + at

v = 45 + (-7) (3) ∵ (-7 ) car is decelerating

v =24 m/s

The final kinetic energy of the car

k.e = 0.5 x 2000 x 24

= 576000 J

The difference in the kinetic energy,

E = K.E - k.e

= 2025000 J - 576000 J

= 1449000 joules

Hence, the change in the Kinetic Energy of the car, E = 1449000 joules

3 0

3 years ago

How do I count atoms in science

VashaNatasha [74]

Answer:

The "2" tells us that there are 2 hydrogen atoms in this compound.

Explanation:

6 0

3 years ago

These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg

Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

$\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C$

Calculating the common potential:

$\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\$

Calculating the charge after redistribution:

$When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2$

$\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\ \\ \to q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C$

6 0

3 years ago