Answer:
A) 588 pounds
Explanation:
According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.
Referring the schematic:
<u>Moment about any point will be zero in equilibrium condition.
</u>
∴Take moment about point L

Answer:
|F| = 393750 N
Explanation:
Given that,
Total mass of the train, m = 750000 kg
Initial speed, u = 84 m/s
Final speed, v = 42 m/s
Time, t = 80 s
We need to find the net force acting on the train. The formula for force is given by :
F = ma

So, the magnitude of net force is 393750 N.
Answer:
That happens to me a few times.
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