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wel
1 year ago
13

Sales of blank______ began to increase in the early 1970s as many cigarette smokers apparently began to look for alternatives th

at would reduce the risk of lung cancer.
Business
1 answer:
antiseptic1488 [7]1 year ago
4 0

(.) Smokeless tobacco products.

<h3>How smoking cigarettes can cause lung cancer?</h3>

According to research, smoking results in cell alterations that lead to lung cancer. Numerous of the hundreds of compounds found in cigarette smoke are carcinogenic. Despite the fact that the human body can frequently detoxify and eliminate carcinogens, when it is unable to do so, residual carcinogens can cause the body's cells to mutate, occasionally resulting in the development of malignant cells. Healthy cells are able to recognize when to stop dividing because the normal cell healing process requires cells to divide continuously until all harm has been fixed. On the other hand, cells that have undergone malignant mutations lose the ability to know when to stop and will continue to divide and expand.

Not every cell mutation results in cancer. But the more smoke a person inhales, the more mutations they'll experience, and the more likely it is that one of those mutations will be malignant. As a result, the chance of developing cancer increases with the length and frequency of a person's smoking. Notably, despite the fact that carcinogens frequently harm lung cells, they can also enter the bloodstream and spread throughout the body, resulting in a variety of cancers.

To know more about cancer visit:-brainly.com/question/14945792

#SPJ4

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Answer:

a)  0.1728

b)  0.09183

c) 0.7354

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Explanation:

Given

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a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

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3 years ago
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