Answer:
I put it in the upload.
Explanation:
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Answer:
5 g of heptane were burned.
Explanation:
Given data:
Mass of CO₂ produced = 15.5 g
Mass of heptane burned = ?
Solution:
Balance chemical equation:
C₇H₁₆ + 11O₂ →7CO₂ + 8H₂O
First of all we will calculate the moles of CO₂ produced.
Number of moles = mass / molar mass
Molar of CO₂ = 44 g/mol
Number of moles = 15.5 g / 44 g/mol
Number of moles = 0.3523 mol
Now we will compare the moles of CO₂ and C₇H₁₆ from balance chemical equation
CO₂ : C₇H₁₆
7 : 1
0.3523 : 1/7 × 0.3523 = 0.05 mol
Mass of C₇H₁₆:
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Mass = 0.05 mol / 100 g/mol
Mass = 5 g
Answer:
Option D. 30 g
Explanation:
The balanced equation for the reaction is given below:
2Na + S —> Na₂S
Next, we shall determine the masses of Na and S that reacted from the balanced equation. This is can be obtained as:
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of S = 32 g/mol
Mass of S from the balanced equation = 1 × 32 = 32 g
SUMMARY:
From the balanced equation above,
46 g of Na reacted with 32 g of S.
Finally, we shall determine the mass sulphur, S needed to react with 43 g of sodium, Na. This can be obtained as follow:
From the balanced equation above,
46 g of Na reacted with 32 g of S.
Therefore, 43 g of Na will react with = (43 × 32)/46 = 30 g of S.
Thus, 30 g of S is needed for the reaction.