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lubasha [3.4K]
3 years ago
11

HELP ASAP ITS TIMED!!!

Chemistry
2 answers:
Tpy6a [65]3 years ago
5 0

Answer:

C would be the right answer

IgorLugansk [536]3 years ago
3 0

Answer:

B

Explanation:

I have a similar question and it was correct try B

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Which equation would you use to solve the following problem? An object is moved 29 meters with a force of 289 N. What is the wor
notsponge [240]

Work done can be calculated from force and distance the object moves.

The equation relating work done, force and distance is,

Work (Joules) = Force (Newton) * Distance (m)

Given the force acting on the object = 289 N

Distance the object moves = 29 m

Calculating the work done from force and distance:

Work = Force * Distance

= 289 N * 29 m

= 8381 J

= 8381 J * \frac{1 kJ}{1000 J} = 8.381 kJ

4 0
3 years ago
For the reaction 2Fe + O2 > 2FeO, how many grams of iron oxide are produced from 5.00 moles of iron?
Greeley [361]

Answer:

359 grams FeO

Explanation:

To find how many grams FeO are produced, you need to use the moles of Fe, convert it to moles of FeO (using the mole-to-mole ratio from the equation), then convert the moles of FeO to grams (using the molar mass from the periodic table).

2 Fe + O₂ --> 2 FeO

Molar Mass (FeO) = 55.845 g/mol + 16.00 g/mol

Molar Mass (FeO) = 71.845 g/mol

5.00 moles Fe           2 moles FeO            71.845 grams
----------------------   x  ------------------------  x  ----------------------  = 359 grams FeO
                                   2 moles Fe               1 mole FeO

5 0
2 years ago
Plz help, I will give brainliest.
baherus [9]

Answer: The value of K_c is 2

Explanation:

Moles of  N_2O_4 = 1.0 mole  

Volume of solution = 1.00 L

Initial concentration of N_2O_4 = \frac{1.0mol}{1.00L}=1.0M

Equilibrium concentration of NO_2 = \frac{1.0mol}{1.00L}=1.0M  

The given balanced equilibrium reaction is,

                            N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initial conc.          1.0 M            0 M

At eqm. conc.     (1.0-x) M      (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

K_c=\frac{(1.0)^2}{(1.0-0.5)}

K_c=2

Thus the value of K_c is 2

4 0
3 years ago
Which term refers to the speed at which reactants are converted into products?
liberstina [14]
Reaction rate , forsure
8 0
3 years ago
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my tens digit is 2 more than my hundreds digit and my ones digit is 1 more than my tens digit. my Hundreds digit is 5. what numb
Marta_Voda [28]
578 is definitely the answer
6 0
3 years ago
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