The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Lydia is at a coffee shop and knows she can spend no more than $65
before tax. She sees this price list in the coffee shop.
Dark Roast Coffee $7.50
Pumpkin Spice Coffee $10.50
Breakfast Tea $23.50
if Lydia buys 1/2 pound of the Breakfast Tea and 2 pounds of the Dark Roast coffee, how many 1- pound bags of Pumpkin Spice coffee can she buy?
Given Information:
Shopping Budge = $65
Price of
Dark Roast Coffee = $7.50
Price of Pumpkin Spice Coffee = $10.50
Price of Breakfast Tea = $23.50
Amount of Breakfast Tea required = 1/2 pound
Amount of Dark Roast coffee required = 2 pounds
Required Information:
How many 1-pound Pumpkin Spice Coffee can she buy = ?
Answer:
n = 3 bags of 1-pound Pumpkin Spice Coffee
Step-by-step explanation:
We are given that the amount of Breakfast Tea required is 1/2 pound so the cost of Breakfast Tea is
Cost of Breakfast Tea = 1/2*23.50 = $11.75
We are also given that the amount of Dark Roast coffee required is 2 pounds so the cost of Dark Roast coffee is
Cost of Dark Roast coffee = 2*7.50
Cost of Dark Roast coffee = $15
We know that total Lydia's total budget is $65
11.75 + 15 + 10.50x = 65
Where x represents the amount of Pumpkin Spice coffee required
10.50x = 65 - 11.75 - 15
10.50x = 38.75
x = 3.64 pounds
That means Lydia can buy 3.64 pounds of Pumpkin Spice coffee.
Now assuming that the Pumpkin Spice coffee is sold only in 1-pound bags then the required number of bags that Lydia can buy is
n = 3.64 pound/1-pound
n = 3.64
Since bags cannot be in fraction so
n = 3 bags
Note: we can not round off to 4 bags since that would surpass the given budged.
