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3 years ago

1. What does c(3) = 60 mean in terms of the problem?

Mathematics

1 answer:

drek231 [11]3 years ago

3 0

C=20 I think the answer is that

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Delvig [45]

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3 years ago

The temperature in several cities in Canada are shown in the table to the right. The average temperature can be found in the sum

aliina [53]

Answer:

The one you selected is right

Step-by-step explanation:

8 0

3 years ago

Find the coordinates of the image of the point (3, 4) after it has been rotated by 180 degrees

sammy [17]

Answer:

(-3,-4)

Step-by-step explanation:

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6 0

3 years ago

A barrel of oil was filled at a constant rate of 7.9 gal/min. The barrel had 12 gallons before filling began.

jenyasd209 [6]

The equation that models this situation is z = 7.9y + 12.

A linear equation is a function that has a single variable raised to the power of 1. An example is x = 4y + 2.

Where:

2 is the constant
x = dependent variable
y = independent variable

From the equation given, 12 would be the constant, the independent variable would be 7.9 and z would be the dependent variable.

z = 7.9y + 12

Here is the complete question: A barrel of oil was filled at a constant rate of 7.9 gal/min. The barrel had 12 gallons before filling began. write an equation in standard form to model the linear situation.

A similar question was answered here: brainly.com/question/2238405

4 0

3 years ago

What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3

andrew-mc [135]

Solve 4x − 3y = 3 and 5x − 4y = 3

Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
 $\frac{4x}{4} = \frac{3x+3}{4}$ [Divide both sides by 4]
x= $\frac{3}{4}y+ \frac{3}{4}$

Step 2: Substitute $\frac{3}{4}y+ \frac{3}{4}$ for x in 5x-4y=3
5x-4y=3
5( $\frac{3}{4}y+ \frac{3}{4}$ )-4y=3
 $\frac{-1}{4}y+ \frac{15}{4} =3$
$\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4}$ [Subtract $\frac{15}{4}$ to both sides]
$\frac{-1}{4}y= \frac{-3}{4}$
$\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }= \frac{\frac{-3}{4} }{ \frac{-1}{4}}$ [Divide both sides by $\frac{-1}{4}$ ]
y = 3

Step 3: Substitute 3 for y in x = $\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}(3)+ \frac{3}{4}$
x = 3

5 0

3 years ago