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Masja [62]
3 years ago
14

1. What does c(3) = 60 mean in terms of the problem?

Mathematics
1 answer:
drek231 [11]3 years ago
3 0
C=20 I think the answer is that
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Help plz I WILL GIVE BRAINLIEST JUST PLZ HELP
-Dominant- [34]

Answer:

3x-4=107* why vertical angles

Step-by-step explanation:

3x-4=107

add 4 on both sides

3x=111*

x=37

6 0
3 years ago
Read 2 more answers
Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Select the property of equality used to arrive at the conclusion <br> if x-3=7 , then x=10
Fantom [35]

Answer:

The addition property of equality  

Step-by-step explanation:

According to the addition property of equality, if we add the same number to each side of an equation, the equality is still true.

We are given the equation

x – 3 = 7, and we must solve for x.

We want to get x by itself, so we <em>add 3 to each side</em>.

x – 3 + 3 = 7 + 3

             x = 10

We have just used the addition property of equality.

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3 years ago
How many ounces are in 50 pounds?
jeka94
A total of 800 ounces.
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Charlotte finds two landscape gardeners online: the first charges a fixed fee of $20 per job plus $15 per hour for labor, while
Damm [24]

$15 per hour for labor plus $5 per hour for labor

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