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MariettaO [177]
1 year ago
8

Which number is greater than 5,043​

Mathematics
2 answers:
Furkat [3]1 year ago
6 0

I don't know if there was supposed to be an image or something attached, but anything greater than 5,043 would be represented in the inequality

x > 5,043.

This includes every number greater than 5,043, including 5,044, 1,000,000, and everything in between and above.

Leno4ka [110]1 year ago
3 0
5,044 is the answer…….
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Here’s the other one, i just need two more that i will be posting, ty your and amazing person
Anuta_ua [19.1K]

Answer:

See below.

Step-by-step explanation:

X-intercepts: (-7, 0) & (-3, 0)

Axis of Symmetry: x = -5

Y-intercept: (0, -21)

Vertex: (-5, 4)

4 0
3 years ago
Write an equation ​(a) in​ slope-intercept form and ​(b) in standard form for the line passing through ​(22​,99​) and perpendicu
liberstina [14]
Y-99=-1/33(x-22)

a). y = 1/33x + 98 1/3

b) 33y = x + 109 1/3
x - 33y = -109 1/3
5 0
3 years ago
Simplify complex numbers:add n subtract complex numbers<br><br>(3-5i) - (8-2i) ​
IgorLugansk [536]

Answer:

-5-3i

Step-by-step explanation:

3-8= -5

-5-(-)2i

-5+2i=-3i

5 0
3 years ago
PLEASE I NEED HELP ​
NeTakaya

Answer:

D) y=-1/2x+4

Step-by-step explanation:

D) y=-1/2x+4

In order to be parallel, it has to have the same slope (-1/2).  Also, if you plug in (-2,5) for x and y, it does pass through those coordinates.

8 0
2 years ago
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

Used:\ (a+b)^2=a^2+2ab+b^2

Answer:\ \boxed{4.8\ units}

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

So. We have the answer! :)

Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

6 0
3 years ago
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