probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
learn more about of probability here
brainly.com/question/11234923
#SPJ4
C I petty sure the answer is c
That's easy you just need to listen in school to answer it
Answer: when you graph it, it opens down so it will have a maximum
Step-by-step explanation:
Answer:
we conclude that Kiera got the right 63 questions.
Step-by-step explanation:
Total questions = 90
The percentage of correct question = 70%
Using the formula
The number of correct questions = 70% of 90
= [70/100] × 90
= 0.7 × 90
= 63
Therefore, we conclude that Kiera got the right 63 questions.
