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OLga [1]
1 year ago
11

Help me cause why not

Mathematics
1 answer:
8090 [49]1 year ago
5 0

a. x = 50, the measure of ∠A = 170°.

b. y = 7, the measure of FE = 14, AB = 14.

In the question, we are given that ΔABC ≅ ΔEFG, that is, triangle ABC is congruent to triangle EFG.

As we know that corresponding parts of congruent triangles are also congruent,

we can write that:

∠A = ∠E,

∠B = ∠F,

∠C = ∠G,

AB = EF,

BC = FG, and

CA = GE.

Now,

a. We are asked to solve for x.

We know that:

∠A = ∠E,

or, 3x + 20 = 5x - 80,

or, 3x - 5x = -80 - 20,

or, -2x = -100,

or, x = -100/-2 = 50.

Also, we are asked to find the measure of ∠A.

∠A = (3x + 20)° = (3*50 + 20)° = 170°.

b. We are asked to solve for y.

We know that,

AB = EF,

or, y + 7 = 3y - 7,

or, y - 3y = - 7 - 7,

or, -2y = -14,

or, y = -14/-2 = 7.

Also, we are asked to find the measure of FE and AB.

FE = 3y - 7 = 3*7 - 7 = 14.

AB = y + 7 = 7 + 7 = 14.

Learn more about congruent triangles at

brainly.com/question/1675117

#SPJ1

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Answer:

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Answer:

y=1/2x+2

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(0,2) and (-4,0).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

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First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=2.

Also, let's call the second point you gave, (-4,0), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-4 and y2=0.

Now, just plug the numbers into the formula for m above, like this:

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So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

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Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(0,2). When x of the line is 0, y of the line must be 2.

(-4,0). When x of the line is -4, y of the line must be 0.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,2) and (-4,0).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

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(-4,0). y=mx+b or 0=1/2 × -4+b, or solving for b: b=0-(1/2)(-4). b=2.

See! In both cases we got the same value for b. And this completes our problem.

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