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1 year ago

Find the value of n and yz if y is between x and z. xy = 4n 3. yz = 2n-7, xz = 20 yz = need help with this question?

Mathematics

1 answer:

Helga [31]1 year ago

3 0

The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.

According to the given question.

We have some linear equations.

xy = 4n + 3

yz = 2n - 7

and

xz = 20

Since, y is between x and z. Which means y, x and z are collinear points.

Therefore,

xy + yz = xz

⇒ 4n + 3 + 2n - 7 = 20

⇒ 6n -4 = 20

⇒ 6n = 20 + 4

⇒ 6n = 24

⇒ n = 24/6

⇒ n = 4

Therefore,

yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1

Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.

Find out more information about collinear points here:

brainly.com/question/1593959

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IRISSAK [1]

Answer:

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Step-by-step explanation:

Given equations:

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From the first equation we get:

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After talking with you here are two different options I think you are trying to ask:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about: $(\frac{-12}{3}) ^{3}$

Answer: -62

Explanation:

PEMDAS tells us we need to do the exponent first:

-12³ = (-12)³ = -1728

The parentheses are important so you cube the negative sign as well!

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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about (-1 $\frac{2}{3}$ )³

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Explanation:

First, let us turn -1 and two thirds into a mixed number:

Ignoring the negative for now, we can 1 times 3 is 3. 3 plus 2 is 5. 5/3 is 5/3. Adding in the negative we get $-\frac{5}{3}$

To cube it we must do:

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So we have 125/27

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Two cancel each other out, and we are left with one (-) so our answer is negative

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