Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer:
Ribosomes
Explanation:
No matter where mitochondrial proteins are made, they are synthesized on Ribosomes that translate messenger RNA into the amino acids that form the protein chain. Most of the proteins in mitochondria function in genome regulation, DNA maintenance, and upkeep of the small percentage of internal mitochondrial proteins.
Answer:
Most likely B).
Explanation:
Dominant traits are the most likely traits, although recessive traits are still possible to pass down, just less likely.
Answer:
The cell may be converted to malignant tumor cell.
Explanation:
Due to failure of lag in the normal repair process, there will be formation of irreparable mutated DNA which may include double-strand breaks and cross-linkages in DNA. Due to this the normal functioning of the cell will be disturbed and there may be formation of malignant tumor or cancer. The normal repair process in necessary for any cell to compensate the mutations in DNA that even occur during division or replication.
