<u>Answer:</u> The amount of drug that must be given is 102.3 grams
<u>Explanation:</u>
We are given:
Weight of the person = 150.0 lb
Converting this weight into kilograms, we use the conversion factor:
1 kg = 2.20 lb
So, 
Applying unitary method:
For 1 kg of body weight, the correct dosage of the drug is 1.50 mg
So, for 68.2 kg of body weight, the correct dosage of the drug will be
Hence, the amount of drug that must be given is 102.3 grams
Answer:
who is anna , and how would i know did was anna a real person and is she dead
Explanation:
Answer:
the appropriate tone to use in this instance would be a stern but kind and understanding tone. you don't want to be too forecul in order to avoid the patient rebelling however, you must be stern since it is a matter of life and death; the best course of action is to be entirely honest about the serious effects his habits have on his health. Based on his past actions of following the regimens prescribed by other doctors, he seems to want to lose weight and do better. The best way is to entirely avoid the point of temptation and try to keep it out of sight and out of mind. being kind is important since people react better to kindness rather than control, showing how much you care could cause the patient to want to do better.
Answer:
Growth hormone.
Explanation:
Human growth hormone is a polypeptide hormone that regulates the growth, cell metabolism and cellular differentiation. The hypo or hyper secretion of this hormone can cause a particular disease in the individual.
The long-term hyposecretion of the growth hormone during childhood and adolescence can lead to the dwarfism. The individual has shorter height than the normal individual in dwarfism.
Thus, the correct answer is option (c).
Most schools agree on the basic elements for pre-medical education. Minimum course requirements include one year each of biology, general (inorganic) chemistry, organic chemistry, physics, and related lab work for each. In addition, about two-thirds require English and about one quarter require calculus.