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-BARSIC- [3]
1 year ago
15

To make a homemade all purpose cleaner, you can use the ingredients shown in the table (1 cup vinegar, ½ cup of rubbing alcohol,

1 gallon water). Samuel has 1 cup of rubbing alcohol and will use the entire amount. He plans to store the cleaning solution in containers that each hold maximum of six cups. How many containers does he need?
Mathematics
1 answer:
vovikov84 [41]1 year ago
5 0

The total solution will include 17.5 cup of vinegar 0.5 cups of rubbing alcohol, and 2 cup of water which is a total of 35 cups of solution. Sofie will need 6 total containers to hold all of the solution.

<h3>Number of container</h3>

1 cup of rubbing alcohol:

1 cup of rubbing alcohol=1÷1/2

1 cup of rubbing alcohol=2

Cup of alcohol needed:

Cup of alcohol needed=1+1/2+16

Cup of alcohol needed=17.5 cups

Total cups:

Total cups=17.5×2

Total cups=35 cups

Number of container:

Number of container=1+35/5

Number of container=1+5

Number of container=6  containers

Therefore the total solution will include 17.5 cup of vinegar 0.5 cups of rubbing alcohol, and 2 cup of water which is a total of 35 cups of solution. Sofie will need 6 total containers to hold all of the solution.

Learn more about Number of container here:brainly.com/question/20533888

#SPJ1

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-3x-y=-17 4x + 2 y equals 20
ExtremeBDS [4]
-3x - y = -17
4x + 2y = 20

multiply one part of the equation so that we can be able to use the process of elimination.

(-3x - y = -17)2
4x + 2y = 20

Now we have:

-6x -2y = - 34
4x+2y= 20
------------------------
-2x = -14

Divide -2 on both sides.

-2x = -14
/-2       /-2

x = -7.


=============================================

To solve for y, we just have to substitute the value of x to any of the equation given above, that we feel comfortable with. And I'm going to choose this equation: 4x + 2y = 20


4x + 2y = 20

4(-7) + 2y = 20

-28 + 2y = 20

Add 28 on both sides

-28 + 2y = 20
+28          +28
---------------------
2y = 48
/2      /2

y = 24.


The last thing you would do is to check if the answers is correct.
All you have to do is plug in the values of x and y into both equations and see if they equal to one another.

You may have to do this by yourself :P

Anyways, if you have any questions about this topic, feel free to PM me or any other users interested. Thank you for being part of Brainly! Have a nice day!










4 0
2 years ago
PLZZZZZZZZZ HELP THERE IS JUST THIS ONE AND IM STILL CONFUSED PLZZZ HELPPPP ME REAL QUICK ITS REALLY EASY
RUDIKE [14]
Angle a is 22.62 degrees
and
angle b is 67.38 degrees

7 0
3 years ago
Which of the following are solutions to the equation below? check all that apply x^2+4x-9=x+1
Aleks04 [339]
The answer is C and D only
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor
vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

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3 years ago
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Vedmedyk [2.9K]

Answer:

The first option and the third option

Step-by-step explanation:

Since the figure moved 4 places down and 4 places to the right.

5 0
3 years ago
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