Question

Solve the following quadratic equation by completing the square: x^2-12x+5=7 PLS HELP ASAP

Answer 1

Answer:

xd

Step-by-step explanation:

xd

Answer 2

Answer:

${x}^{2} - 12x + 5 = 7$

i) move constants to the right-hand side and change its sign

${x}^{2} - 12 {x} = 7 - 5$

ii) subtract the numbers

${x}^{2} - 12x = 2$

iii) add (12/2)² to both sides of the equation

${x}^{2} - 12x + ( \frac{12}{2} ) {}^{2} = 2 + ( \frac{12}{2} ) {}^{2}$

iv) using a²-2ab+b²=(a-b)² , factorize the expression

$(x - \frac{12}{2} ) {}^{2} = 2 + ( \frac{12}{2} ) {}^{2}$

v) calculate the value

$(x - \frac{12}{2}) {}^{2} = 2 + 36$

$(x - \frac{12}{2}) {}^{2} = 38$

vi) reduce the fraction

$(x - 6) {}^{2} = 38$

vii) solve the equation for x

$x - 6 = + - \sqrt{38}$

1) first value of x

$x - 6 = \sqrt{38}$

$x = \sqrt{38} + 6 \: or \: 12.16$

2) second value of x

$x - 6 = - \sqrt{38}$

$x = - \sqrt{38} + 6 \: or \: - 0.16$