How can I convert 35/21 two mixed numbers written in simplest form!Help Me please

1 answer:

4 0

First you would subtract 21 from 35 to determine how many fractions of 1 you would have left so you would start with 1 and 14/21, then you would find the largest number that goes into both 14 and 21 which is 7 and divide by that so the total simplified answer would be 1 and 2/3! hope this helped!!!

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Fittoniya [83]

Answer:

QSR = 68º

Step-by-step explanation:

TSQ + QSR = TSR

15x + (10x - 2) = 173

Combine like terms

25x = 175

Divide both sides by 25

x = 7

QSR = 10x - 2

QSR = 10(7) - 2

QSR = 68º

5 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .