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Mrac [35]
2 years ago
6

Question 1 i need help on

Mathematics
1 answer:
ladessa [460]2 years ago
6 0

The actual distance between Bixby and Coyle is 105 miles which can be represented by 7 cm.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

60 miles = 4 cm

Hence:

7 cm = 7 cm * (60 miles)/(4 cm)  = 105 miles

The actual distance between Bixby and Coyle is 105 miles which can be represented by 7 cm.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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What is the equation and solution for. D=12 for 4d-24-12=0
vladimir1956 [14]
It's very difficult to understand the question.  In fact, I have
not achieved that lofty level yet.

-- If  d = 12,  then  ( 4d - 24 - 12 )  is not equal to zero.

-- If  ( 4d - 24 - 12 )  IS equal to zero, then  d = 9, not 12 .
5 0
3 years ago
Read 2 more answers
IMG_1444.PNG ( please answer these WITH YOUR WORK SHOWING!) it’s okay if you don’t know them all but please some of them answere
Setler79 [48]
#18)  (√2)/(2y)
#19)  7x/5
#20)  (2√5)/5
#21)  (3√5)/5
#22)  √5/b
#23)  (2√(2n))/n
#24)  (2√15)/15m

For #18:
\sqrt{\frac{18y}{36y^3}}=\sqrt{\frac{1}{2y^2}}=\frac{1}{y\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2y}

#19:
\sqrt{\frac{49x^5}{25x^3}}=\sqrt{\frac{49x^2}{25}}=\frac{7x}{5}

#20:
\frac{\sqrt{12}}{\sqrt{15}}=\frac{2\sqrt{3}}{\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{45}}{15}=\frac{6\sqrt{5}}{15}=\frac{2\sqrt{5}}{5}

#21:
\frac{\sqrt{72}}{\sqrt{40}}=\frac{6\sqrt{2}}{2\sqrt{10}}=\frac{3\sqrt{2}}{\sqrt{10}}\times \frac{\sqrt{10}}{\sqrt{10}}=\frac{3\sqrt{20}}{10}=\frac{6\sqrt{5}}{10}=\frac{3\sqrt{5}}{5}

#22:
\sqrt{\frac{25b}{5b^3}}=\sqrt{\frac{5}{b^2}}=\frac{\sqrt{5}}{b}

#23:
\sqrt{\frac{24}{3n}}=\sqrt{\frac{8}{n}}=\frac{2\sqrt{2}}{\sqrt{n}}\times \frac{\sqrt{n}}{\sqrt{n}}=\frac{2\sqrt{2n}}{n}

#24:
\sqrt{\frac{8}{30m^2}}=\sqrt{\frac{4}{15m^2}}=\frac{2}{m\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{15}}{15m}
3 0
4 years ago
A student drops their notes and their papers scatter. The fact that the papers scatter and do not remain neatly stacked is an il
Serggg [28]

Answer:

-- increase in entropy

-- second law of thermodynamics

Step-by-step explanation:

The 1st law of thermodynamic states that there is conservation of energy, i.e. we cannot create energy and we cannot destroy energy also in an isolated system.

The given example is not a representative of the 1st law.

The \text{2nd law of thermodynamics} states that there is a natural tendency of an isolated system to \text{degenerate} into a more \text{disordered state.} Before dropping the notes and papers were in an isolated ordered system.

After dropping the papers scattered and did not remain in a stack position. It moves into a more disordered state.

Begore dropping down the notes and papers, they were in a stable position, i.e. no kinetic energy is there. No randomness when the notes and the papers were dropped. There is an increase in kinetic energy. There is randomness among the molecules by bombardment. So there is an increase in entropy.

Thus, above illustrations represents :

  • an increase in entropy
  • the second law of thermodynamics
8 0
3 years ago
You track your commute times for three weeks (15 days), recording the following times in minutes: 17, 16, 20, 24, 22, 15, 21, 25
ale4655 [162]

Answer:

b) 15,90,24.133,20

c) New average = 19.4, New Median = 20

d) 8

e) 40%

f) Wednesday

Step-by-step explanation:

a)                    Mon  Tue  Wed  Thu  Fri    

     Week 1      17      16     20     24   22

     Week 2     15      21    25     17    90

     Week 3      16      17    22     20   20

This is a 3×5 matrix where the rows gives us the weeks(Week 1, Week 2, Week 3) and the columns are the weekdays(Mon, Tue, Wed, Thu, Fri).

b)The shortest duration out of the data given for fifteen days is 15 minutes.

The longest duration is 90 minutes.

To calculate the average of given data, we use the following formula:

Average  = \frac{\text{Sum of all observations}}{\text{Total no of observations}}

=\frac{17+16+20+24+22+15+21+25+17+90+16+17+22+20+20}{15}

=\frac{362}{15}

=24.133

Median = the value that divides the data into two equal parts]

Ascending order: 15,16,16,17,17,17,20,20,20,21,22,22,24,25,90

Median = (\frac{n+1}{2})\text{th term} = 8th term = 20

c)                   Mon  Tue  Wed  Thu  Fri    

     Week 1      17      16     20     24   22

     Week 2     15      21    25     17     19

     Week 3      16      17    22     20   20

New average = \frac{\text{Sum of new observations}}{\text{Total no of observations}}

=\frac{17+16+20+24+22+15+21+25+17+19+16+17+22+20+20}{15}

=\frac{362}{15}

=19.4

New Median

Ascending order: 15,16,16,17,17,17,19,20,20,20,21,22,22,24,25

Median = (\frac{n+1}{2})\text{th term} = 8th term = 20

d) In order to know how many times we commute for 20 minutes or more, we check the entries that are greater than or equal to 20 minutes. We have 8 such entries. Thus, 8 times the commute was 20 minutes or more longer.

e)  Percent of commutes less than 18 minutes = \frac{\text{Commutes that are less than 18 minutes}}{\text{Total number of commutes} }× 100%

=\frac{6}{15}×100% = 40%

f) Average  = \frac{\text{Sum of all observations}}{\text{Total no of observations}}

Average time spent in commuting on Monday = 16

Average time spent in commuting on Tuesday = 18

Average time spent in commuting on Wednesday = 22.3

Average time spent in commuting on Thursday = 20.3

Average time spent in commuting on Friday= 20.3

On Wednesday, we spent the most on commute time.

7 0
3 years ago
Please help and thank you
Marta_Voda [28]

×≧4 is the answers that is what my teacher told me

7 0
4 years ago
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