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Delicious77 [7]
2 years ago
8

A pool company is creating a blueprint for a family pool and a similar dog pool for a new client. Which statement explains how t

he company can determine whether pool LMNO is similar to pool PQRS?
Translate PQRS so that point P of PQRS lies on point L of LMNO, then dilate PQRS by the ratio segment LM over segment PQ.
Translate PQRS so that point Q of PQRS lies on point M of LMNO, then dilate PQRS by the ratio segment PQ over segment LM.
Translate PQRS so that point P of PQRS lies on point L of LMNO, then translate PQRS so that point Q of PQRS lies on point M of LMNO.
Translate PQRS so that point Q of PQRS lies on point M of LMNO, then translate PQRS so that point P of PQRS lies on point L of LMNO.

Mathematics
1 answer:
Charra [1.4K]2 years ago
3 0

The statement that explains how the company can determine whether pool LMNO is similar to pool PQRS is;

B. Translate PQRS so that point Q of PQRS lies on point M of LMNO, then dilate PQRS by the ratio segment PQ over segment LM.

<h3>How to carry out Transformations?</h3>

Given that quadrilaterals ABCD and EFGH are similar:

The corresponding points on the quadrilaterals are:

P → L

Q → M

R → N

S → O

So, the first step is any of the following:

Translate point P to L

Translate point Q to M

Translate point R to N

Translate point S to O

Notice that the side lengths of PQRS are bigger than that of LMNO

This means that the Quadrilateral PQRS has to be dilated (compressed) by a ratio of side lengths of LMNO divided by side lengths of PQRS

For example, the point M is translated to point Q. The figure will then be dilated by a ratio of LM divided by PQ.

Read more about Transformations at; brainly.com/question/4289712

#SPJ1

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Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?
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An angle bisector divides an angle into two equal halves.

The measure of angle \angle CPD is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

\angle RPD = 140^o, and line PC bisects \angle RPD

Because line PC bisects \angle RPD, then it means that the measure of RPD is twice the measure of CPD:

So, we have:

\angle RDP = 2 \times \angle CPD

Substitute \angle RPD = 140^o

140^o = 2 \times \angle CPD

Divide both sides by 2

70^o = \angle CPD

Apply symmetric property of equality:

\angle CPD = 70^o

Hence, the measure of angle \angle CPD is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

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