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Lorico [155]
3 years ago
8

A warden meets with 23 prisoners. He tells them the following:

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0
The prisoners could do a pattern that could signal who has already been in the room. So for example, one light off, both lights off, one light on, both lights off. But with left and right lights to make the sequence last as long as possible. Then after that sequence to have the last one be the signal that everyone has been in there. I dunno this is tricky lol
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3

Step-by-step explanation:

Remember the order of operations using PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).  So, you get  18 - 6   / 5-1  = 12/4 = 3

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Find the missing side or angle.<br> Round to the nearest tenth.<br> C=5<br> b=4<br> a=2<br> B=[ ? ]°
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Answer:

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Step-by-step explanation:

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The triangles are congruent by
hichkok12 [17]

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Step-by-step explanation:

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2 years ago
A passbook saving account has a rate of 6%. find the effective annual yield, rounded to the nearest tenth of a percent, if the i
irinina [24]

Answer:

a,b,c,d,e,f) The effective annual yield is 1.1P-P = 0.1P = 10%P.

Step-by-step explanation:

This is a compound interest problem

Compound interest formula:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

n: number of times that interest is compounded per unit t

t: time the money is invested or borrowed for.

a)

r = 0.06

n: 2(semianually means that the interest is compounded twice a year).

t = 1.

A = P(1 + \frac{0.06}{2})^{2*1}

A = 1.1P

The acount started the year with P, and it ended with 1.1P, so the effective annual yield is 1.1P-P = 0.1P = 10%P.

b)

Now we have n = 3, since if the interest is compounded quarterly, is is compounded three times a year(a year has 3 quarters). So:

A = P(1 + \frac{0.06}{3})^{3*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

c) Now we have n = 12, since the interest is compounded monthly, and there are 12 months a year. So:

A = P(1 + \frac{0.06}{12})^{12*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

d) Since the interest is compounded daily, and we assume 360 days in a year, n = 360. So:

A = P(1 + \frac{0.06}{360})^{360*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

e) The interest is compounded 1000 times a year, so n = 1000

A = P(1 + \frac{0.06}{1000})^{1000*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

f) The interest is compounded 100000 times a year, so n = 100000

A = P(1 + \frac{0.06}{100000})^{100000*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

6 0
3 years ago
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