Answer:
NaOH is limiting
Explanation:
Hcl + NaOH ------------ Nacl + H2O
Given 7.81g 5.24g
mol weights 1+35.5 23+16+1
36.5 40
No of Moles 7.81/36.5 5.24/40
0.2139 0.131
No of moles = weight/ molecular weight
No of moles of NaOH is lower so it is limiting as according to equation one mole of Hcl requires mole of NaOH so equal number of moles are required. NaOH is 0.131 which is far lower than 0.2139
-------- represents arrow in forward direction in equation
Answer:
Weight of solution produced = 5135 kg
Amount of water removed = 4865 kg
Explanation:
For the balance of mass, the incoming mass of sugar must be equal to the outgoing mass. So, the incoming mass (mi) is 38% of 10000 kg
mi = 0.38x10000 = 3800 kg
The outgoing mass (mo) must be 3800 kg, and it is 74% of the total mass (mt)
mo = 0.74xmt
0.74xmt = 3800
mt = 3800/0.74
mt = 5135 kg
This is the mass of solution produced.
The amount of water removed (wr) is the amount of water incoming (wi) less the amount of water outgoing (wo). Both will be the total mass less the mass of sugar :
wi = 10000 - 3800 = 6200 kg
wo = 5135 - 3800 = 1335 kg
wr = wi - wo
wr = 6200 - 1335
wr = 4865 kg
Hello,
I believe this is (25 g Al) * (1 mol H / 1.008 g H) = 24.8015 mol H
Hopefully that was the right approach.
I thought that if one mole of Al is
26.982 g, then the numbers of moles for H (1.008 g/mol) would be about 25 mol.
If it doesn’t make sense or if you have resources/notes to which I can refer, I’ll see what I can do!
Good luck!
Kr 5s2 is the correct noble gas configuration for strontium
