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natita [175]
2 years ago
5

So that your grandmother can listen to A Prairie Home Companion, you take her bedside radio to the hospital where she is staying

. You are required to have a maintenance worker test the radio for electrical safety. Finding that it develops 120 \mathrm{~V} on one of its knobs, he does not let you take it to your grandmother's room. Your grandmother complains that she has had the radio for many years and nobody has ever gotten a shock from it. You end up having to buy a new plastic radio.(a) Why is your grandmother's old radio dangerous in a hospitals
Physics
1 answer:
g100num [7]2 years ago
4 0

The old radio will not be safe in a hospital and buying a new one is the best thing to do as to prevent the risk of her or other individuals getting electrocuted.

<h3>What is Voltage?</h3>

This is referred to as the difference in electric potential between two points or the work done which is needed per unit to move a charge between two points in a circuit.

All individuals have varying skin resistance which is why exposure to that radio which develops 120V on one of its knobs may lead to electrocution or other types of injuries to the grandma or other individuals in the hospital.

This is therefore the reason why the old radio will be dangerous in a hospital environment.

Read more about Resistance here brainly.com/question/17563681

#SPJ4

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What is kinematics??? explain!!!​
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Answer:

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A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distan
OleMash [197]

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Speed of the car, v = 100 km/h = 27.77 m/s

The coefficient of kinetic friction of the tires, \mu_k=0.5

Let f is the net force acting on the body due to frictional force, such that,

-f=ma

a=\dfrac{-f}{m}

a=\dfrac{-\mu _k mg}{m}

a=\mu_k g

a=-0.5\times 9.8

a=-4.9\ m/s^2

We know that the acceleration of the car in calculus is given by :

v.dv=a.dx, x is the stopping distance

\int\limits^0_v {v.dv}=\int\limits^x_0 {a.dx}

\dfrac{v^2}{2}|_v^0=ax

0-(27.77)^2=-2\times 4.9x

On solving the above equation, we get, x = 78.69 meters

So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.

6 0
3 years ago
Find the first three harmonics of a string of linear mass density 2.00 g/m and length 0.600 m when the tension in it is 50.0 n.
blsea [12.9K]

As we know that Nth harmonic of the string is given by

f = \frac{N}{2L}\sqrt{\frac{T}{m/L}}

now here we will have

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Length = L = 0.600 m

Tension = T = 50.0 N

now from above formula we have

f = \frac{N}{2(0.600)}\sqrt{\frac{50.0}{0.002}}

f = 131.8N

now for first harmonic N = 1

f_1 = 131.8 Hz

for second harmonic N = 2

f_2 = 263.5 Hz

for third harmonic N = 3

f_3 = 395.3 Hz

8 0
4 years ago
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