All categories

3 years ago

How do microwaves use the behavior and characteristics of the electromagnetic wave to function?

Physics

1 answer:

serg [7]3 years ago

6 0

Answer:

Radiation moves out of the microwave into waves causing heat.

Explanation:

Inside your microwave oven, electrical energy is transformed into EM energy in the magnetron. When the microwave photons interact with food, food molecules are physically agitated, transforming the EM energy into kinetic energy, or energy of movement .

Hope it helped!

You might be interested in

The atmospheric pressure above a swimming pool changes from 753 to 772 mm of mercury. the bottom of the pool is a rectangle (11

Evgesh-ka [11]

Change in pressure : 772-753 = 19 mm Hg
Since 1 mm Hg = 133 Pa Hg
Then, 19 mm Hg = 2527 Pa Hg
Area of rectangular pool = L* B = 11 x 21 = 231 m^2
To find the force, we multiply the area by the change in pressure: 2527 (231) = 583737N

5 0

3 years ago

Read 2 more answers

The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon

Kryger [21]

Answer:

aaa

Explanation:

$m_e$ = Mass of the Earth = 5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$r_1$ = Distance from the center of the Moon to the center of Earth = 6371000 m

$r_2$ = Distance from the center of the earth center to sun center

$m_m$ = Mass of moon = $7.35\times 10^{22}\ kg$

M = Mass of sun = $1.989\times 10^{30}\ kg$

$F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N$

$F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N$

$\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566$

Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center

4 0

3 years ago

A basketball player makes a bounce pass by throwing the ball with a speed of 5.3 m/s and at an angle 12° below the horizontal. I

Dima020 [189]

Answer:

ball hit the ground from her feet is 1.83 m far away

Explanation:

given data

speed = 5.3 m/s

angle = 12°

height = 1 m

to find out

how far from her feet ball hit ground

solution

we consider here x is horizontal component and y is vertical component

so in vertical

velocity will be = v sin12

vertical speed u = 5.3 sin 12 = 1.1 m/s downward

and

in horizontal , velocity we know v = 5.3 m/s

so from motion of equation

s = ut + 0.5×a×t²

s is distance t is time a is 9.8

put all value

1 = 1.1 ( t) + 0.5×9.8×t²

solve it we get t

t = 0.353 s

and

horizontal distance is = vcos12 × t

so horizontal distance = 5.3×cos12 × ( 0.353)

horizontal distance = 1.83 m

so ball hit the ground from her feet is 1.83 m far away

5 0

3 years ago

To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a ho

Fudgin [204]

This question is incomplete, the missing image is uploaded along this answer.

Answer:

the coefficient of friction is 0.32

Explanation:

Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

ω = 3.9612 rad/s

The centripetal force acting on the sample is;

Fc = mrω²

from the image; r = 200 mm = 0.2 m

so we substitute

Fc = m(0.2 m ) ( 3.9612 rad/s )²

Fc = (3.13822 m/s²)m

we know that the frictional force between the two materials should be providing the necessary centripetal force to rotate the sample object;

f = Fc

μN = Fc

μmg = (3.13822 m/s²)m

μ = (3.13822 m/s²)m / mg

μ = (3.13822 m/s²) / g

acceleration due to gravity g = 9.8 m/s²

μ = (3.13822 m/s²) / 9.8 m/s²

μ = 0.32

Therefore, the coefficient of friction is 0.32

5 0

3 years ago

Juan inflates a balloon and then releases its end to let the balloon go free as air comes out. The balloon then flies around the

sergeinik [125]

action and reaction forces

7 0

3 years ago