1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara31 [8.8K]
3 years ago
5

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

acting on the object?
a
150 N
b
15 N
c
0 N
d
1.5 N
Question 2 (1 point)
A 3 kg object is moving in circular motion at a speed of 4 m/s. The radius of the circle is 4 m. What is the centripetal force acting on the object?

a
0 N
b
24 N
c
12 N
d
48 N
Question 3 (1 point)
An object is moving in circular motion. The centripetal acceleration of the object is 10 m/s^2. If the radius of the circle is 10 m, what is the speed, v, of the object?

a
0 m/s
b
10 m/s
c
5 m/s
d
100 m/s
Question 4 (1 point)
A race car is driving around a circular track that has a radius of 10 m. If the speed of the car is 5 m/s, what is the centripetal acceleration of the car?

a
2.5 m/s^2
b
5 m/s^2
c
10 m/s^2
d
0 m/s^2
Question 5 (1 point)
An object is moving clockwise in circular motion, as shown in the picture below. When the object is at the position shown in the picture, the centripetal force is...



a
an arrow pointing left.
b
an arrow pointing upward.
c
an arrow pointing downward.
d
an arrow pointing right.
Question 6 (1 point)
A ball is spun clockwise in a circular path, as shown below. When the ball is at the position in the picture, the net force acting on the ball...



a
is an arrow pointing up.
b
is an arrow pointing down.
c
is an arrow pointing left.
d
is 0.
Question 7 (1 point)
A ball is spun counter-clockwise, as shown in the picture below. When the ball is at the position in the picture, the velocity is...



a
0
b
an arrow pointing left.
c
an arrow pointing downward.
d
an arrow pointing upward.
Question 8 (1 point)
If the speed of an object in circular motion is tripled, what change will occur in the centripetal force?

a
The centripetal force will be 9X greater than it was.
b
The centripetal force will be the same.
c
The centripetal force will be 3X greater.
d
The centripetal force will be 1/9 as much as it was.
Question 9 (1 point)
If the speed of an object in circular motion is doubled, what change occurs in the centripetal force?

a
The centripetal force is the same.
b
The centripetal force is 2X bigger.
c
The centripetal force is 4X bigger.
d
The centripetal force is 4X smaller.
Question 10 (1 point)
If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?

a
The centripetal force will be 4X bigger.
b
The centripetal force will be the same.
c
The centripetal force will be 1/2 as big as it was.
d
The centripetal force will be 2X bigger.
Physics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = 10ms^{-2}, F = ma = 15*10 = 150N

2) m = 3kg, v = 4ms^{-1}, r = 4m, F = \frac{mv^{2} }{r}

\frac{3*4^{2} }{4} = 12N

3) a = 10ms^{-2}, r = 10m, v=?

F = \frac{mv^{2} }{r} and F = ma

equating the two equations and cancelling a, we have:

\frac{v^{2} }{r} = a

making v the subject of formula, we have:

v = \sqrt{ar}

= \sqrt{100}

= 10ms^{-1}

4) r = 10m, v = 5ms^{-1}, a = ?

F = \frac{mv^{2} }{r}

F = ma

equating the above equations and making a subject of formula, we get:

a = \frac{v^{2} }{r}

a = 25/10 = 2.5ms^{-2}

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

F = (3v)^{2}

F = 9v^{2}

We can see that the force will be 9X greater than it was.

9) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is doubled

F = (2v)^{2}

F = 4v^{2}

We can see that the force will be 4X greater than it was.

10) F = \frac{mv^{2} }{r}

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

You might be interested in
Name the nutrients required for the<br>body.​
Anettt [7]

Answer:

1- water

2- fat

3- carbohydrates

4- vitamins

5- minerals

6 0
3 years ago
Inside a freely falling runaway elevator, your
nasty-shy [4]

The answer is apparent weight is zero.

You are still accelerating downwards at 9.8m/s^2 (if you are on Earth).

You still are being affected by the Earth's gravity.

Not all because of the previous two statements.

Not none because apparent weight is zero as you are falling.

7 0
3 years ago
Read 2 more answers
A has the magnitude 14.4 m and is angled 51.6° counterclockwise from the positive direction of the x axis of an xy coordinate sy
Ad libitum [116K]

Answer:

à in unit vector notation = 12.26485i + 7.54539j

B in unit vector notation = 16.3516i + 3.11529j

Explanation:

The detailed steps and calculation is shown in the attachment.

7 0
3 years ago
The current in a single-loop circuit with one resistance R is 6.3 A. When an additional resistance of 3.4 Ω is inserted in serie
Dmitry [639]

Answer:

10.15Ω

Explanation:

From ohm's law,

V = IR...................... Equation 1

Where V = Voltage, I = current, R = resistance.

Assume the voltage across the resistance = V,

Given: I = 6.3 A

Substitute into equation 1

V = 6.3R.................. Equation 2

When an additional resistance of 3.4 Ω is inserted in series with R,

The voltage remain the same, but the current changes

Total Resistance(Rt) = (R+3.4)Ω, I' = 4.72 A

Also from ohm' law,

V = I'Rt............... Equation 3

Substitute the value of I'  and Rt into equation 3

V = 4.72(R+3.4)............... Equation 5.

Divide equation 2 by equation 5

V/V = 6.3R/4.72(R+3.4)

1 = 1.335R/(R+3.4)

1 = 1.335R/(R+3.4)

R+3.4 = 1.335R

3.4 = 1.335R-R

3.4 = 0.335R

R = 3.4/0.335

R = 10.15Ω

6 0
3 years ago
Read 2 more answers
A physics student throws a softball straight up into the air. The ball was in the air for a total of 3.56 s before it was caught
meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2} (Eq. 1)

Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

v_{o} - Initial velocity of the softball, measured in meters per second.

t - Time, measured in seconds.

g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

3\cdot v_{o} -44.132\,m= 0

v_{o} = 14.711\,\frac{m}{s}

The initial velocity of the softball is 14.711 meters per second.

8 0
3 years ago
Other questions:
  • What is a metric unit for energy?
    14·1 answer
  • Which type of energy is thermal energy a form of?
    15·1 answer
  • You expend 500 w of power in moving a piano 5 meters in 10 seconds. how much force did you exert?
    7·2 answers
  • Help me with this question plss!! :) ​
    9·1 answer
  • As the bell rings, which energy transformation occurs? A. Mechanical energy is converted into sound energy. B. Chemical energy i
    15·2 answers
  • HELPP!!!! URGENT!!!!
    11·1 answer
  • A 2,100 kg car drives east toward a 55 kg shopping cart that has a velocity of 0.50 m/s west. The two objects collide, giving th
    15·2 answers
  • A cargo plane loses one of it's shipments mid
    5·1 answer
  • HELP ASAP
    12·1 answer
  • A car moving at a speed of 20 m/s has a kinetic energy of 200,000 J from that motion. What is the car's mass?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!