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lara31 [8.8K]
3 years ago
5

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

acting on the object?
a
150 N
b
15 N
c
0 N
d
1.5 N
Question 2 (1 point)
A 3 kg object is moving in circular motion at a speed of 4 m/s. The radius of the circle is 4 m. What is the centripetal force acting on the object?

a
0 N
b
24 N
c
12 N
d
48 N
Question 3 (1 point)
An object is moving in circular motion. The centripetal acceleration of the object is 10 m/s^2. If the radius of the circle is 10 m, what is the speed, v, of the object?

a
0 m/s
b
10 m/s
c
5 m/s
d
100 m/s
Question 4 (1 point)
A race car is driving around a circular track that has a radius of 10 m. If the speed of the car is 5 m/s, what is the centripetal acceleration of the car?

a
2.5 m/s^2
b
5 m/s^2
c
10 m/s^2
d
0 m/s^2
Question 5 (1 point)
An object is moving clockwise in circular motion, as shown in the picture below. When the object is at the position shown in the picture, the centripetal force is...



a
an arrow pointing left.
b
an arrow pointing upward.
c
an arrow pointing downward.
d
an arrow pointing right.
Question 6 (1 point)
A ball is spun clockwise in a circular path, as shown below. When the ball is at the position in the picture, the net force acting on the ball...



a
is an arrow pointing up.
b
is an arrow pointing down.
c
is an arrow pointing left.
d
is 0.
Question 7 (1 point)
A ball is spun counter-clockwise, as shown in the picture below. When the ball is at the position in the picture, the velocity is...



a
0
b
an arrow pointing left.
c
an arrow pointing downward.
d
an arrow pointing upward.
Question 8 (1 point)
If the speed of an object in circular motion is tripled, what change will occur in the centripetal force?

a
The centripetal force will be 9X greater than it was.
b
The centripetal force will be the same.
c
The centripetal force will be 3X greater.
d
The centripetal force will be 1/9 as much as it was.
Question 9 (1 point)
If the speed of an object in circular motion is doubled, what change occurs in the centripetal force?

a
The centripetal force is the same.
b
The centripetal force is 2X bigger.
c
The centripetal force is 4X bigger.
d
The centripetal force is 4X smaller.
Question 10 (1 point)
If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?

a
The centripetal force will be 4X bigger.
b
The centripetal force will be the same.
c
The centripetal force will be 1/2 as big as it was.
d
The centripetal force will be 2X bigger.
Physics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = 10ms^{-2}, F = ma = 15*10 = 150N

2) m = 3kg, v = 4ms^{-1}, r = 4m, F = \frac{mv^{2} }{r}

\frac{3*4^{2} }{4} = 12N

3) a = 10ms^{-2}, r = 10m, v=?

F = \frac{mv^{2} }{r} and F = ma

equating the two equations and cancelling a, we have:

\frac{v^{2} }{r} = a

making v the subject of formula, we have:

v = \sqrt{ar}

= \sqrt{100}

= 10ms^{-1}

4) r = 10m, v = 5ms^{-1}, a = ?

F = \frac{mv^{2} }{r}

F = ma

equating the above equations and making a subject of formula, we get:

a = \frac{v^{2} }{r}

a = 25/10 = 2.5ms^{-2}

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

F = (3v)^{2}

F = 9v^{2}

We can see that the force will be 9X greater than it was.

9) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is doubled

F = (2v)^{2}

F = 4v^{2}

We can see that the force will be 4X greater than it was.

10) F = \frac{mv^{2} }{r}

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

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A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat
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Explanation:

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Acceleration can be defined as rate of change of velocity.

a = \frac{dv}{dt}

for calculating acceleration, initial and final velocity are required in meter per second and the total time of the trip in seconds. Then acceleration is measured in meter per second square.

Thus, Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the <u>Time</u> of the total trip in seconds.

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