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just olya [345]
1 year ago
8

A figure is made up of a square and a rectangle. The area of the square is 64 cm². The breadth of the rectangle is the same leng

th of the square. If the total area of the figure is 232 cm², what is the perimeter of the whole figure? ​
Mathematics
1 answer:
antoniya [11.8K]1 year ago
6 0

Answer:

90 cm

Step-by-step explanation:

Let the side of the square be S

Area of the square = S² = 64

So, S = √64 = 8 cm

Let L be the length of the rectangle and B be the breadth

We know B = S = 8

Area of rectangle = BL = 8L

Total area = Area of square + area of rectangle

Total area   = 64 + 8L  = 232  (given)

Subtracting 64 from both sides yields

8L = 232-64 = 168 or L = 168/8 = 21

Perimeter of square = 4S = 4 x 8 = 32

Perimeter of rectangle = 2(B + L) = 2(8 + 21) = 2 x 29 = 58

Total perimeter = 32 + 58 = 90 cm

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What is the constant of variation,k, of the direct variation,y=kx,through (5,8)
grigory [225]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form \frac{y}{x}=k or y=kx

where

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3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

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n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

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