Let William be x years old.
Thomas = (4 + x) years
In five years,
William = (x + 5) years
Thomas = 4 + x + 5 = (9 + x) years
Given, in five years sum of their ages is 24.
x + 5 + 9 + x = 24
2x + 14 = 24
2x = 24 - 14
2x = 10
x =

x = 5
Hence, William is 5 years old and Thomas is 9 years old.
Answer:
and
are the locations higher than
foot
Step-by-step explanation:
We are given that Meg found one treasure at
foot
We are supposed to find Which of these location are higher than
foot?
i) 
So, this location is not higher than
foot
ii)
So, 
So, this location is higher than
foot
iii) - 1 foot

So,this location is not higher than
foot
iv)-2 feet
So,this location is not higher than
foot
v)
So, this location is higher than
foot
Https://www.illustrativemathematics.org/content-standards/tasks/703 check it out it might help
A(b-c)=ab-ac
(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14
now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h
<span>A cube has 6 square faces, so each face would have area 200 sq in/6=33.33 sq in
Since the area of each face equals the square of the sides, the edge of the cube would be = approx. 5.77 in</span>