Answer:
a1= 1 q= −sinx , dla |q| <1 , ta suma jest zbieżna
a1 1
S=
=
1 −q 1+sinx
w mianowniku podobnie: a1=1 , q= sinx , dla | sinx| <1
1
S=
1 −sinx
i mamy równanie:
1
1+sinx
= tg2x
1
1− sinx
Step-by-step explanation:
Answer: y = -4x
Step-by-step explanation: You would use the formula y = mx + b to solve your problem. When you plug the numbers in, you get y = -4x. There would be no "+ b" because in this case, the y-intercept (b) is equal to zero. Therefore, you would not need to write "y = -4x + 0" because that would not be the equation in its simplest form.
Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq =
= 
cosq =
= 
(2,4)
Step-by-step explanation:
I'm not sure in the slightest but with the formula I learned I think this is correct