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1 year ago

You deposit money into an

Mathematics

1 answer:

nadya68 [22]1 year ago

7 0

The amount of money you deposit into the account is $3000

<h3>How much money did you deposit into the account? </h3>

The given parameters are

Rate, r = 8%

Time, t = 5 years

Interest, I = $1200

The formula of simple interest is

I = PRT

So, we have

1200 = I * 8% * 5

This gives

1200 = I * 0.4

Divide both sides by 0.4

I = 3000

Hence, the amount of money you deposit into the account is $3000

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4(2x-3)+8(x-4)=2(2x+6) help plzzz

TEA [102]

Answer:

x = 14/3

Step-by-step explanation:

4(2x-3)+8(x-4)=2(2x+6)

Distribute

8x -12 +8x - 32 = 4x +12

Combine like terms

16x -44 = 4x+12

Subtract 4x

16x-4x -44 = 4x+12-4x

12x -44 =12

Add 44 to each side

12x-44+44 = 12+44

12x = 56

Divide each side by 12

12x/12 = 56/12

x = 14/3

8 0

3 years ago

Read 2 more answers

Find the distance travelled by Rubina if she takes 4 rounds of rectangular park whose length and breadth is 45m and 30m

ANTONII [103]

Length (l) = 45 m
Breadth (b) = 30 m
We know, perimeter of a rectangle = 2(length + breadth)
Therefore, perimeter of the rectangle
= 2(I + b)
= 2(45 + 30) m
= 2 × 75 m
= 150 m
So, the distance travelled by Rubina
= 4 × 150 m
= 600 m

Answer:

The distance travelled by Rubina is 600 m.

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0

2 years ago

204, 200,196,... find the 31st term

rewona [7]

Answer:

31st term = 84

Step-by-step explanation:

Given:

204, 200,196,...

Find:

31st term

Computation:

204, 200,196,...

First term a = 204

Difference d = a3 - a2

Difference d = 196 - 200

Difference d = -4

An = a + (n-1)d

A31 = 204 + (31-1)(-4)

A31 = 204 - 120

A31 = 84

6 0

3 years ago

Read 2 more answers

How do you solve 2x^2+4x=3+3x^2?

allochka39001 [22]

Answer:

5x^2+4x=3

Step-by-step explanation:

You add the like terms: 3x^2 and 2x^2, you get 5x^2. You can't do anything else because there are no more terms that are alike.

So the answer would be 5x^+4x=3

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3 years ago

Consider the following functions.G(x) = 4x2; f(x) = 8x(a)

noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form $4x^2+C$ is an antiderivative of 8x

Step-by-step explanation:

A function F is an antiderivative of the function f if

$F'(x)=f(x)$

for all x in the domain of f.

(a) If $f(x) = 8x$ , then $G(x)=4x^2$ is an antiderivative of f because

$G'(x)=8x=f(x)$

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of f.

(b) Because

$\frac{d}{dx}(4x^2)=8x$

then $G(x)=4x^2$ is an antiderivative of $f(x) = 8x$ . Therefore, every antiderivative of 8x is of the form $4x^2+C$ for some constant C, and every function of the form $4x^2+C$ is an antiderivative of 8x.

8 0

3 years ago