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Using the Normal distribution, it is found that 0.0359 = 3.59% of US women have a height greater than 69.5 inches.
In a <em>normal distribution</em> with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
US women’s heights are normally distributed with mean 65 inches and standard deviation 2.5 inches, hence .
The proportion of US women that have a height greater than 69.5 inches is <u>1 subtracted by the p-value of Z when X = 69.5</u>, hence:
has a p-value of 0.9641.
1 - 0.9641 = 0.0359
0.0359 = 3.59% of US women have a height greater than 69.5 inches.
You can learn more about the Normal distribution at brainly.com/question/24663213
Explicación paso a paso:
La distancia recorrida el primer día = 500 m
Si aumenta la distancia en 200 m diariamente, entonces el total corrido diariamente formará una progresión aritmética con el último término de 10 km (10,000) como se muestra;
500, (500 + 200), (500 + 200 + 200) ... 10,000
500, 700, 900 ... 10,000
para que sepamos el número total de días usados para la carrera, usaremos la fórmula para calcular el enésimo término de una secuencia aritmética como se muestra;
where;
n es el número de términos
a es el primer término de la secuencia
d es la diferencia común
Dado a partir de la secuencia:
a = 500
Tn = 10,000
d = 700-500 = 900-700 = 200
Sustituir en la fórmula y calcular el valor de n
Andrea habría alcanzado los 10.000km tras 48,5 días de carrera