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yanalaym [24]
2 years ago
14

Find cos ⁡ ( 2 ⋅ ∠ A B C ) cos(2⋅∠ABC)

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0

The value of the cosine function is -0.385

<h3>How to determine the measure of the cosine function?</h3>

The figure that completes the question is added as an attachment

From the figure, we have the following sides

AB = √13

AC  = 3

BC = 2

The triangle is a right triangle.

The angle B is calculated as:

cos(B) = 2/√13

Evaluate

cos(B) = 0.5547

Take the arccos of both sides

B = 56.31

This means that:

cos(ABC) = cos(56.31)

Multiply ABC by 2.

So, we have:

cos(ABC * 2) = cos(56.31 * 2)

Evaluate the product

cos(ABC * 2) = cos(112.62)

Evaluate the cosine

cos(ABC * 2) = -0.385

Hence, the value of the cosine function is -0.385

Read more about cosine function at

brainly.com/question/17075439

#SPJ1

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Cosine = Adjacent over Hypotenuse (CAH)

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