Find cos ( 2 ⋅ ∠ A B C ) cos(2⋅∠ABC)
1 answer:
The value of the cosine function is -0.385
<h3>How to determine the measure of the cosine function?</h3>The figure that completes the question is added as an attachment
From the figure, we have the following sides
AB = √13
AC = 3
BC = 2
The triangle is a right triangle.
The angle B is calculated as:
cos(B) = 2/√13
Evaluate
cos(B) = 0.5547
Take the arccos of both sides
B = 56.31
This means that:
cos(ABC) = cos(56.31)
Multiply ABC by 2.
So, we have:
cos(ABC * 2) = cos(56.31 * 2)
Evaluate the product
cos(ABC * 2) = cos(112.62)
Evaluate the cosine
cos(ABC * 2) = -0.385
Hence, the value of the cosine function is -0.385
Read more about cosine function at
#SPJ1
You might be interested in
About 12.56 units.
Solve for x by plugging in values into Pythagorean theorem.
Simplify
Subtract 144 from both sides
divide both sides by 2
complete the square
take the square root of both sides.
subtract by 6 to get about 17.28 for x.
Plug in values for x to get distance traveled on outside of the yard.
17.28 + (17.28 +12) = 46.56
subtract 34 from the length to get the difference in travel. 46.56-34=12.56
Solve for x by plugging in values into Pythagorean theorem.
Simplify
Subtract 144 from both sides
divide both sides by 2
complete the square
take the square root of both sides.
subtract by 6 to get about 17.28 for x.
Plug in values for x to get distance traveled on outside of the yard.
17.28 + (17.28 +12) = 46.56
subtract 34 from the length to get the difference in travel. 46.56-34=12.56