Answer:
The radius of the spherical tank is 12 meters
Step-by-step explanation:
In this question, we are tasked with calculating the radius of the spherical tank given the volume of air it can hold
Mathematically, the volume V of a sphere is 4/3 * pi * r^3
Thus, 7234.56 = 4/3 * 3.14 * r^3
7,234.56 = 4.19 * r^3
r^3 = 7234.56/4.19
r^3 = 1,728
r = cube root of 1,728
r = 12 meters
32. (a) For an even function, f(x) = f(-x). Given f(5) = 3, we know f(-5) = 3.
Therefore (-5, 3) is also on the graph.
For an odd function, f(-x) = -f(x). Given f(5) = 3, we know f(-5) = -3.
Therefore (-5, -3) is also on the graph.
33. f(-x) = -f(x). The function is odd.
34. f(-x) = x/(x-1) ≠ -f(x) ≠ f(x). The function is neither even nor odd.
35. f(-x) = f(x). The function is even.
I believe it would be as following:
x+7>12
Here, x represents the unknown number. The symbol for no less than is greater than.
Answer:
Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead
Step-by-step explanation:
Mariana workings:
-3(2x - 4) = -12
-6x - 12 = -12
Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead
-6x = 0
x=0
Correct workings:
-3(2x - 4) = -12
-6x + 12 = - 12
-6x = -12 - 12
-6x = -24
x = -24/-6
x = 4
The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.
Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter
. Thus, from the given information we can conclude that:


Cross-multiplying we get:

grams.
Thus, the amount of water in grams in that Kool-aide is 80 grams.