Answer:
9.
h(x)=-x-1
let y =-x-1
interchanging role of x & y
x=-y-1
y=-x-1
h-¹(x)=-x-1
again
f(x)=(2-3x)/2
let
y=(2-3x)/2
interchanging role of x & y
x=(2-3y)/2
2x-2=-3y
y=(2-2x)/3
f-¹(x)=(2-2x)/3
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>i</u><u>n</u><u>v</u><u>e</u><u>r</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u>.</u>
10.
f(x)=-x+3
let y=-x+3
interchanging role of x & y
x=-y+3
y=3-x
f-¹(x)=-x+3
equal to g(x)=-x+3
<u>Given function are</u><u> inverse of each other.</u>
<span> all of our square numbers from 1 to 80 are 1, 4, 9, 16, 25, 36, 49, 64. </span>
Answer:
Part 1. 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.
Variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking job.
Part 2. The income from shift of work at the diner that is 50x, and the income from dog walking work that is 17y.
Part 3. The total income from the diner is given by 50x.
Step-by-step explanation:
Each week, Aubrey earns $50 for every shift he works at the diner and $17 for every dog-walking job.
He uses the expression (50x + 17y) to keep track of his earning.
Part 1. Here the coefficient of the expressions 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.
And the variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking jobs.
Part 2. Therefore, there are two terms in the expression, one is the income from the shift of work at the diner that is 50x and the other is the income from dog walking work that is 17y.
Part 3. The total income from the diner is given by 50x. (Answer)
Answer:
p^(a-1)
Step-by-step explanation:
The simplified expression can be seen in the picture attached below
As the factors have the same base, we just need to add or substract the exponents
p^(a-3+2) = p^(a-1)
x-5= 0
move -5 to the other side
sign changes from -5 to +5
x-5+5= 0+5
x= 5
x-6= 0
x-6+6= 0+6
x= 6
Answer: B. 5 and 6
