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tekilochka [14]
2 years ago
5

HELPPPPPPPPPPP MEEE PLS

Mathematics
1 answer:
ivanzaharov [21]2 years ago
4 0

Answer:

See explanation below

Step-by-step explanation:

If the base of a radical exponent is the same then the following properties hole and x≠ 0

\sqrt[n]{x} = x^{\frac{1}{n}   Rule 1

\frac{x^m}{x^n} = x^{m-n}   Rule 2

(x^m)^n = x^{mn}   Rule 3

The numerator in the expression is

\sqrt[3]{x^2y^5} =(x^2)^\frac{1}{3} (y^5)^\frac{1}{3} = x^\frac{2}{3}} . y ^ \frac{5}{3}  Using rules 1 and 3

The denominator is

\sqrt[4]{x^3y^4} =(x^3)^\frac{1}{4} (y^4)^\frac{1}{4} = x^\frac{3}{4}} . y ^ 1} Using rules 1 and 3

Therefore the original expression in exponent form is

\frac{x^\frac{2}{3} y ^ \frac{5}{3}}{x^\frac{3}{4} y ^ 1}}  

Using rule 2 we get the final expression as

x^{\frac{2}{3}-\frac{3}{4}}$ $y^{\frac{5}{3}-1}

2/3 - 3/4 = 8/12 - 9/12 = -1/2

5/3 - 1 = 5/3 - 3/3 = 2/3

So the final expression is

$x^{-\frac{1}{12}}y^{\frac{2}{3}}$

Proved

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What is the domain of the function y=2√x-6?<br> 88AX&lt;∞<br> O 0≤x&lt;∞<br> 3≤x&lt;∞<br> 6≤x&lt;∞
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Answer:

If the x-6 is all under the sqrt, the last answer is right:

6<= x <= infinity

If only x is under the sqrt and - 6 is NOT under the sqrt, then:

0 <= x <= infinity is the correct answer.

Step-by-step explanation:

You can look at the equation and or graph to determine the domain of a function. The domain is all the x's that may go into the equation or all the x's on the graph of the function. Inside of a squareroot symbol the number inside there must be positive. While considering the equation, only x's that keep that inside positive can be used.

For sqrt(x-6), x has to be 6 or bigger.

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vladimir2022 [97]

Answer:

<em>Answer:</em> 3) \sqrt{5}

Step-by-step explanation:

<u>Radical Form and Exponent Form</u>

A radical can be expressed as a rational exponent following the identity:

\displaystyle \sqrt[m]{x^n}=x^\frac{n}{m}

We should also recall that:

(x^n)^m=x^{nm}

We are given the expression:

\displaystyle \left(5^{\frac{3}{4}}\right)^\frac{2}{3}

Applying the power of power:

\displaystyle \left(5^{\frac{3}{4}}\right)^\frac{2}{3}=\left(5^{\frac{3}{4}\cdot \frac{2}{3}}\right)

Simplifying:

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