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Illusion [34]
2 years ago
9

A store spends 1/4 of its income on salaries and 1/6 of its income on advertising. If the store pays $150,000 for salaries, how

much does it spend on advertising? Be sure to explain your reasoning.
Mathematics
1 answer:
Contact [7]2 years ago
8 0

Answer:

$100,000

Step-by-step explanation:

Let the total income of the store = \$x

Total spends on salaries = \frac{1}{4} of total income

Total spends on advertising = \frac{1}{6} of total income

Also, we are given that:

Total money paid as salaries = $150,000

To find:

Total spends on advertising ?

Solution:

As per question statement, we can write the following equation:

\dfrac{1}{4}x =\$150000\\\Rightarrow x =\$150000\times 4\\\Rightarrow x = \$600000

Now, as per the given statement, <em>total spends on advertising</em> are:

\dfrac{1}{6}x =\dfrac{1}{6}\times 600000 = \bold{\$100,000 }

Therefore, the answer is <em>$100,000</em>

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Help! 10 Points not 5!
KATRIN_1 [288]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

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The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

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3 years ago
WILL GIVE BRAINLIEST!!!!! Mariah cuts a rectangle along its diagonal. Two congruent triangles are created. The two angles create
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Answer:

Stated Below:

Step-by-step explanation:

x + y = 90 because the 2 angles add up to 90 .

Now, m < x = five times  m < y, so x = 5y or y = x/5

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7 0
2 years ago
4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are
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Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.

Hypergeometric distribution:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • 1000 people means that N = 1000
  • 130 can wiggle their ears, thus k = 130
  • Two are selected, thus n = 2.

The probability that neither can wiggle his or her ears is P(X = 0), thus:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0
2 years ago
A store had 235 MP3 players in the month of January. Every month, 30% of the MP3 players were sold and 50 new MP3 players were s
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The answer is A cause 30% is 0.7 and f(n-1) equals the amount being sold the +50 is for every 50 new one and the the 235 is for what they started with                                         
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Find the area please​
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144 I believe. You multiply length times width
5 0
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