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algol13
3 years ago
15

I really need help with this please I keep getting it wrong and I’m confused

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0
18+5= n
n= 23
D. 23
15+5=20 so u just gotta add 5 to 18
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What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)
Vesna [10]

Hello from MrBillDoesMath!

Answer:  

@ =   pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)


Discussion:

Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)

where

4cos(@) - 2 = 0.                Adding 2 to both sides

4 cos(@) - 2 +2 = 2  =>

4 cos(@) = 2                     Divide both sides by 4

cos(@) = 2/4 = 0.5


This implies that @ =   pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)


Thank you,

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5 0
3 years ago
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Answer:

Tyree and all of his friends get 1 ticket for $7. Next they all get 1 snack for $5. Then they all get a drink for $2. So:

1=7

1=5

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Then you take each person (which there are five of then) and you times all five people by 7, 5, 2.

5 x 7=35

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Step-by-step explanation:

your welcome

4 0
3 years ago
Read 2 more answers
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
If two of these congruent angels have the same degree measure and angle 1 is (3x+10)degrees and Angie 2 is (5x-4) degrees set th
ddd [48]

Answer:

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14 = 2x

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3 years ago
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Answer:

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Option 3 is actually quadratic. This is similar to a arithmetic, except instead, the amount added to the number is multiplied by 2 every time.

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4 0
2 years ago
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