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algol13
3 years ago
15

I really need help with this please I keep getting it wrong and I’m confused

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0
18+5= n
n= 23
D. 23
15+5=20 so u just gotta add 5 to 18
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Determine if events A and B are mutually exclusive.
gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

P(A) = \frac{1}{4}

P(B) = \frac{3}{5}

P(A\ or\ B) = \frac{7}{10}

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

P(A\ or\ B) = P(A) + P(B)

So, we have:

P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}

Take LCM

P(A\ or\ B) = \frac{5+12}{20}

P(A\ or\ B) = \frac{17}{20}

By comparing:

P(A\ or\ B) = \frac{17}{20} ---- Calculated

P(A\ or\ B) = \frac{7}{10} ---- Given

We can conclude that A and B are not mutually exclusive because:

\frac{17}{20} \ne \frac{7}{10}

6 0
3 years ago
Solve for x <br><br> -7(1-8x)=105
Sunny_sXe [5.5K]
-7 + 56x = 105
56x = 105 + 7
56x = 112
x = 2
4 0
4 years ago
Solve the system of equations.<br> 3x+4y=−23<br> x=3y+1<br> x=<br> y=<br> ​
Romashka-Z-Leto [24]

Answer:

i think  {x,y} = {-5,-2}  

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
Find the volume of the given solid: Bounded by the cylinder y^2+z^2=4 and the planes x = 2y, x = 0, z = 0 in the first octant.
rodikova [14]

The solution would be like this for this specific problem:

<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫ 0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [ -2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [ 2·r² ] dr </span>
<span>= (2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>

So the volume of the given solid is 16/3. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0
4 years ago
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