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Ghella [55]
2 years ago
9

How could you represent 0.614 using only 5 tenths

Mathematics
2 answers:
astraxan [27]2 years ago
6 0

Answer: 6.14/10

Step-by-step explanation:

kaheart [24]2 years ago
5 0

We can represent 0.614 using only 5 tenths as \mathbf{\dfrac{6.14}{10}}

<h3>What is a decimal number?</h3>

A decimal is a number that is divided into two parts: a whole and a fraction. Between integers, decimal numbers are used to express the numerical value of complete and partially whole quantities.

The accepted method for representing both integer and non-integer numbers is the decimal number system.

From the given information, we are to represent 0.614 by using only 5 tenths.

  • 5 tenths can be mathematically expressed as:
  • \mathbf{=\dfrac{5}{10}}

Representing 0.614 in the same form, we have:

\mathbf{=\dfrac{0.614\times 1000}{1\times 1000}}

\mathbf{=\dfrac{614}{1000}}

\mathbf{=\dfrac{6.14}{10}}

Learn more about representing decimals in the fractional form here:

brainly.com/question/2877484

#SPJ 10

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The measure of an angle is 104° What is the measure of its supplementary angle?
boyakko [2]

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76°

Step-by-step explanation:

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supplementary angle = 180° - 104°= 76°

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What is 3x-2y=-16 in slope intercept form
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Answer:

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Step-by-step explanation:

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What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

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The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
3 years ago
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