Question

The lons entering the mass spectrometer have the same charges. After being accelerated through a potential difference of 8.20 kV, a
singly charged 12c+ ion moves in a circle of radius 19.4 cm in the magnetic field of a mass spectrometer. What is the magnitude of the
field? Use these atomic mass values: 12C, 12.0 u; 14C, 14.0 u; 160, 15.99 u. The conversion between atomic mass units and kilograms is
1u=1.66 x 10-27 kg.

Answer 1

The calculated magnitude is  6.73 x 10³ V/m.

AMU is described as being one-twelfth the mass of a carbon-12 atom (12C). C makes up more than 98% of the carbon that can be found in nature, making it the most prevalent isotope. The magnitude of the field is the change in potential across a small distance in the indicated direction divided by that distance.

Potential difference = 8.20 kV= 8.20 x 10³ V

radius= 19.4/100=0.194 m

total distance that is circumference of the circle= 2πr =2 x 3.14 x 0.194

                                                                               = 1.218 m

therefore Magnitude= 8.20 x 10³ / 1.218

                                  =6.73 x 10³ V/m

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