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3 years ago

A large truck is moving at 22.0 m/s. If its momentum is 125,000 kg • , what is the truck's mass?

Physics

2 answers:

PIT_PIT [208]3 years ago

6 0

The mass of the truck is 5680 kg

alexandr402 [8]3 years ago

6 0

Answer:

5682 kg

Explanation:

The momentum of a moving object is given by:

$p=mv$

where m is the mass of the object while v is its velocity.

In this problem, we know the velocity of the truck (v=22.0 m/s) and its momentum (p=125,000 kg m/s), therefore we can rearrange the previous formula to calculate the mass of the truck:

$m=\frac{p}{v}=\frac{125,000 kg m/s}{22.0 m/s}=5682 kg$

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ss7ja [257]

Answer:

The convex lens is shaped so that all light rays that enter it parallel to its axis cross one another at a single point on the opposite side of the lens.

Explanation:

3 0

3 years ago

In one hour, coal supplies 500 000 J of energy. The energy amounts to 380 000 J. How much useful energy is produced in one hour?

Debora [2.8K]

Answer:

120,000J

Corrected question;

In one hour, coal supplies 500 000 J of energy. The wasted energy amounts to 380 000 J. How much useful energy is produced in one hour?

Explanation:

Given;

Total energy Et = 500,000 J

Wasted Energy Ew = 380,000J

The amount useful energy is the amount of energy that is available for supply.

This can be derived by subtracting the wasted energy from the total energy.

Useful energy = Total Energy - wasted energy

Eu = Et - Ew

Substituting the given values;

Eu = 500,000J - 380,000

Eu = 120,000 J

The amount of useful energy produced in one hour is 120,000 J

5 0

3 years ago

Select all the correct answers.

amid [387]

Answer:

Explanation:

because in the moving object there's a certain energy applied

8 0

3 years ago

A train travels 76 kilometers in 2 hours and then 54 kilometers in 5 hours .What is the average speed ?

gizmo_the_mogwai [7]

V = d ÷ t --> bc d=vt
V = (76+54)÷(2+5) = 130÷7 = 18.57km/hr

7 0

3 years ago

An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis. What is the magnitude of the flux of t

Ede4ka [16]

Answer:

The magnitude of the flux of electric field through a square of surface area is zero.

Explanation:

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$\phi_E=E.A\,cos\,(90^o)\\\\\phi_E=0$

4 0

3 years ago