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3 years ago

Covert 35000000 miles to meters and show how you got the answer?

Physics

1 answer:

Lina20 [59]3 years ago

8 0

Answer:

56327040000 metres

Explanation:

1 mile =

1609.344 metres

35000000 miles = x meters

we represent x by the number of meters which the requested miles maps to

we cross multiply, so 1609.344×35000000 = 1 × x

x =56327040000 metres

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A 0.299 kg mass slides on a frictionless floor with a speed of 1.44 m/s. The mass strikes and compresses a spring with a force c

VMariaS [17]

Answer:

x = 0.12 m

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

(m)×(v^2) = (k)×(x^2)

x^2 = [(m)(v^2)]/k

x = \sqrt{ [(m)(v^2)]/k}

x = \sqrt{ [(0.299)((1.44)^2)]/(44.9)}

x = 0.12 m

Therefore, the mass will travel 0.12 m and come to rest.

= 0.491 m/s

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3 years ago

Work is the product of ___<br> _ and an object's displacement.

emmasim [6.3K]

Answer:

Force

Explanation:

W= F * d

7 0

3 years ago

lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this l

ser-zykov [4K]

<h2>Question: </h2>

The nearpoint of an eye is 151 cm. A corrective lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this lens?

Answer:

29.96cm

Explanation:

Using the corrective lens, the image should be formed at the front of the eye and be upright and virtual.

Now using the lens equation as follows;

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ -------------(i)

Where;

f = focal length of the lens

v = image distance as seen by the lens

u = object distance from the lens

From the question;

v = -151cm [-ve since the image formed is virtual]

u = 25cm

Rewrite equation (i) to have;

$f = \frac{uv}{u+v}$

Substitute the values of v and u into the equation;

$f = \frac{25*(-151)}{25-151}$

$f = \frac{-3775}{-126}$

f = 29.96cm

The focal length should be 29.96cm

4 0

3 years ago

A young woman was found dead on the side of the road. Two witnesses said they saw and red cadillac hit her and drive off earlier

nignag [31]

I think the answer would be A. Density because many headlights could have the same density, but the rest of the analysis techniques would be specific to that crime.

7 0

3 years ago

B. Projectile on cliff (range)

dimulka [17.4K]

Answer:

x = 41.28 m

Explanation:

This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.

Let's start by using trigonometry to find the initial velocity

cos 25 = v₀ₓ / v₀

sin 25 = Iv_{oy} / v₀

v₀ₓ = v₀ cos 25

v_{oy} = v₀ sin 25

v₀ₓ = 22 cos 25 = 19.94 m / s

v_{oy} = 22 sin 25 = 0.0192 m / s

let's use movement on the vertical axis

y = y₀ + v_{oy} t - ½ g t²

when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m

0 = 21 + 0.0192 t - ½ 9.81 t²

4.905 t² - 0.0192 t - 21 = 0

t² - 0.003914 t - 4.2813 =0

we solve the quadratic equation

t = $\frac{ 0.003914\ \pm \sqrt{0.003914^2 + 4 \ 4.2813 } }{2}$

t = $\frac{0.003914 \ \pm 4.13828}{2}$

t₁ = 2.07 s

t₂ = -2.067 s

since time must be a positive scalar quantity, the correct result is

t = 2.07 s

now we can look up the distance traveled

x = v₀ₓ t

x = 19.94 2.07

x = 41.28 m

5 0

3 years ago