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1 year ago

The sum of three numbers is 3068.Two of the numbers are 1266 and 1755,find the third number

Mathematics

2 answers:

Virty [35]1 year ago

7 0

Answer:

Step-by-step explanation:

3068 - 1266 - 1755 = 47

ratelena [41]1 year ago

3 0

Answer:

The third number is 47.

Step-by-step explanation:

The sum of three numbers is 3068 - this can be expressed mathematically as:

$\displaystyle{x + y + z = 3068}$

Given that two of the numbers are 1266 and 1755 (in order) then substitute x = 1266 and y = 1755:

$\displaystyle{1266 + 1755 + z = 3068}$

Find the third number - solve for z-variable:

$\displaystyle{3021 + z = 3068}\\\\\displaystyle{z = 3068-3021}\\\\\displaystyle{z = 47}$

Therefore, the third number is 47.

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natita [175]

Answer:

$2+2-1-1+6=x : x = 8$

Step-by-step explanation:

$2+2-1-1+6=x\\$

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$x=2+2-1-1+6$

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8 0

3 years ago

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Answer:

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2 years ago

Find the value of y for the given value of x.

tia_tia [17]

X=30 in the first one and x=-15 in the second one

5 0

3 years ago

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The cost for the raw materials of marble countertops, C s can be represented by the function c(a) = 4.25a , where a is the area

tatyana61 [14]

Answer:

m(c(a)) = 4.8875a can be used to find the marked-up price of a marble countertop depending on the area

Step-by-step explanation:

We are given that The cost for the raw materials of marble countertops, C s can be represented by the function c(a) = 4.25a --------1

a = area of the countertops.

we are also given that The retail markup, m, can be represented by the function m(c) = 1.15c.

We are supposed to find function can be used to find the marked-up price of a marble countertop depending on the area?

Marked up price function : m(c) = 1.15c.

Substitute the value of c form 1

Marked up price function of a marble countertop depending on the area:

m(c(a))=1.15(4.25 a)

m(c(a))= 4.8875 a

So, Option 1 is true

Hence m(c(a)) = 4.8875a can be used to find the marked-up price of a marble countertop depending on the area

5 0

3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago

The sum of three numbers is 3068.Two of the numbers are 1266 and 1755,find the third number​

The sum of three numbers is 3068.Two of the numbers are 1266 and 1755,find the third number