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svetoff [14.1K]
2 years ago
10

Solving equations 73=-6(k-7) + 6(k+5)

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
4 0

Answer:

K = -5.2

Step-by-step explanation:

I hope this helped

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Jaime adds equations A and B to solve this system of equations. Why is this method
just olya [345]

The elimination method is valid for the system of equation because the y term cancels.

<h3>How to solve a system of equation using elimination method?</h3>

The system of equation can be solved using elimination methods.

Therefore,

x - 2y = 3

3x + 2y = 17

Hence,

x + 3x  = 4x

-2y + 2y = 0

3 + 17 = 20

Therefore,

4x = 20

The y term cancels. Therefore, we can solve for x and later solve for y.

learn more on equation here: brainly.com/question/17746153

#SPJ1

8 0
2 years ago
Solve for x 1-6x=-17
Zarrin [17]

Answer:

x=3

Step-by-step explanation:

1. Rearrange terms

1 - 6x = -17

-6x + 1 = -17

2. Subtract 1 from both sides of the equation (we want to get rid of 1)

3. Simplify

In the end, you should get x=3.

3 0
3 years ago
10)<br>Simplify the expression.<br>6(4x + 12) – 9x - 18 - 4(-6)<br>​
aleksklad [387]

Answer:

\boxed{\bold{15x+78}}

Step By Step Explanation:

Apply Rule - (-a) = a

\bold{6\left(4x+12\right)-9x-18+4\cdot \:6}

Multiply: 4 · 6 = 24

\bold{6\left(4x+12\right)-9x-18+24}

Expand \bold{6\left(4x+12\right): \ 24x+72}

= \bold{24x+72-9x-18+24}

Simplify \bold{24x+72-9x-18+24}

= \bold{15x+78}

━ Mordancy ━

4 0
3 years ago
A fourth grade class of 28 students is given a standardized math test. The mean score of the 12 boys is 25 with a standard devia
Mashcka [7]

Answer:

The standard error for the sampling distribution is 1.323.

Step-by-step explanation:

Let <em>X</em> = scores of girls and <em>Y</em> = scores of boys.

The information provided is:

\bar x=24\\s_{x}=4\\n_{x}=16\\\bar y=25\\s_{y}=3\\n_{y}=12

As the population standard deviations are not known, use a pooled standard deviation to estimate the standard error of the sampling distribution.

The formula of pooled standard deviation is:

S_{p}=\sqrt{\frac{s_{x}^{2}}{n_{x}^{2}}+\frac{s_{y}^{2}}{n_{y}^{2}}}

Compute the standard error for the sampling distribution as follows:

SE=\sqrt{\frac{s_{x}^{2}}{n_{x}^{2}}+\frac{s_{y}^{2}}{n_{y}^{2}}}=\sqrt{\frac{4^{2}}{16}+\frac{3^{2}}{12}}=\sqrt{1+\frac{9}{12}}=\sqrt{\frac{21}{12}}=1.323

Thus, the standard error for the sampling distribution is 1.323.

7 0
3 years ago
a box contains 5 chocolate chip cookies, 4 sugar and 6 oatmeal raisin. what is the probability of picking a chocolate chip cooki
LenaWriter [7]

Answer:

5 out of 15

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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