P = 3r + 2s --> P - 3r = 3r - 3r + 2s
2s = P - 3r --> 2s/2 = (P - 3r)/2
s = (P - 3r)/2
Answer:
Option C is the right answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
- (f×g)(x) = 2x^2 +2x
- (f×g)(x) = 6y^2 -11y -35
Step-by-step explanation:
The distributive property applies.
1. (fg)(x) = f(x)·g(x) = (2x)·(x +1)
(f×g)(x) = 2x^2 +2x
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2. (fg)(x) = f(x)·g(x) = (2y -7)·(3y +5) = 2y(3y +5) -7(3y +5)
(f×g)(x) = 6y^2 -11y -35
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<em>Additional comment</em>
Please note in problem 2 that the function argument is x and the variable in the given expressions is y. This means the function value is exactly and only <em>6y^2 -11y -35 for any value of x</em>. It does not change when x changes. (We suspect a typo.)