Step-by-step explanation:
11.68-0.48
= 11.20
11.20÷1.6
= 7.0 or 7
ahh this is the correct answer.
so if it helps don't forget to like and Mark me.
Answer:
I am not sure but I think the correct answer is c
<span>2 and 3/4 punds of roast beef 2 3/4 = (4x2) + 3 /4= 11/4 roast beef
</span><span>1 and 7/8 pounds of turkey 1 7/8 = 15/8 </span>turkey
2 1/16 pounds of salami 2 1/16 33/16 <span>salami
</span><span>if you put 1/4 of pound of meat
</span>then 11/4 roast beef divided by 1/4 = 11/4 x4 = 11 sandwiches roast beef
15/8 turkey<span> divided 1/4 = 15/8 x 4 = 15/2 = 7 sandwishes
</span>
33/16 salami divided <span> 1/4 = 33/16 x 4 = 33/ 4 = 8 sandwiches</span>
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
I got 4.5 for question 2 and 597 1/4 for question 6. Idk if im right