1. Because each element in the domain is matched exactly with one element I. The range.
I assume the question was true or false. Here is how you verify the identity— which is true :)
To simplify the function, we need to know some basic identities involving exponents.
1. b^(ax)=(b^x)^a=(b^a)^x
2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)
Now simplify f(x), where
f(x)=(1/3)*(81)^(3*x/4)
=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]
=(1/3)(3^(4*3*x/4) [ rule 1 above ]
=(1/3) (3^(3*x)
=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]
(A) Initial value is the value of the function when x=0, i.e.
initial value
= f(0)
=(1/3)(3^(3x))
=(1/3)(3^(3*0))
=(1/3)(3^0)
=(1/3)(1)
=1/3
(B) the simplified base base is 3 (or 27 if the other form is used)
(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).
(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).
If you get a 0 on it your grade will drop 5%
The cell labelled a is a joint frequency of 48 and the cell labelled b is a marginal frequency of 93.
<h3>What is a frequency table?</h3>
The frequency of an occurrence or a value is the number of times it happens. A frequency table is a list of objects with the frequency of each item shown in the table.
The data is mentioned in the table given below:
We need to find the value of a and b.
Here, Cell Phone+No Cell Phone=Total
To find a:
Add the no lap entries, that is 159+a=207
⇒a=48
To find b:
Add the lap entries, that is 82+11=b.
⇒b=93.
Therefore, the cell labelled a is a joint frequency of 48 and the cell labelled b is a marginal frequency of 93.
To learn more about the frequency table visit:
brainly.com/question/12576014.
#SPJ1