Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Step-by-step explanation:
Here are the options:
A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.
B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:
= 11/(11 + 12) = 11/23 = 0.4783
At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:
= 41 / (41 + 48) = 41/85= 0.4824
Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Answer: (Mayadc821 wrote this anwser check theyre account for more)
Since you know the x and y values, you just have to plug these into the linear slope-intercept equation:
y = mx + b
-10 = m(1) + b
m + b = -10
b = -10 - m
Now that we have a value for b, we can plug this into the other equation:
8 = m(-8) + b
8 = -8m + (-10 - m)
8 = -9m -10
18 = -9m
m = -2
Now that we know what m is equal to, we can plug this into our first equation to get an answer for b:
b = -10 - m
b = -10 -(-2)
b = -10 + 2
b = -8
Our final equation is y = -2x - 8
The value of m is 35 degrees, because the right angle is 90 degrees, therefore, 90-55=35.
The value of t is 55 degrees because is perpendicular to the other 55 degree angle.
Answer:
Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279
Step-by-step explanation:
Let the number of red fish and blue fish in the large tank are x and y respectively.
Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.
Since in each tank ratio of the red fish to blue fish is 333 : 444
That means x : y = 333 : 444
Or ![\frac{x}{y}=\frac{333}{444}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B333%7D%7B444%7D)
⇒ ![\frac{x}{y}=\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B3%7D%7B4%7D)
⇒ y =
--------(1)
Similarly x' : y' = 333 : 444
⇒ ![\frac{x'}{y'}=\frac{333}{444}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%27%7D%7By%27%7D%3D%5Cfrac%7B333%7D%7B444%7D)
⇒ ![\frac{x'}{y'}=\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%27%7D%7By%27%7D%3D%5Cfrac%7B3%7D%7B4%7D)
⇒ x' =
------(2)
Ratio of the fish in large tank to the fish in small tank is 464646 : 555
So (x + y) : (x' + y') = 464646 : 555
![\frac{x+y}{x'+y'}=\frac{464646}{555}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2By%7D%7Bx%27%2By%27%7D%3D%5Cfrac%7B464646%7D%7B555%7D)
Now we replace the values of x and y' from equation (1) and equation (2)
![\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%2B%5Cfrac%7B4x%7D%7B3%7D%29%7D%7B%28%5Cfrac%7B3y%27%7D%7B4%7D%2By%27%29%7D%3D%5Cfrac%7B464646%7D%7B555%7D)
![\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B7x%7D%7B3%7D%7D%7B%5Cfrac%7B7y%27%7D%7B4%7D%7D%3D%5Cfrac%7B464646%7D%7B555%7D)
![\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20%5Cfrac%7Bx%7D%7By%27%7D%3D%5Cfrac%7B464646%7D%7B555%7D)
![\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%27%7D%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20%5Cfrac%7B464646%7D%7B555%7D)
![\frac{x}{y'}=\frac{232323}{370}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%27%7D%3D%5Cfrac%7B232323%7D%7B370%7D)
![\frac{y'}{x}=\frac{370}{232323}](https://tex.z-dn.net/?f=%5Cfrac%7By%27%7D%7Bx%7D%3D%5Cfrac%7B370%7D%7B232323%7D)
![\frac{y'}{x}=\frac{10}{6279}](https://tex.z-dn.net/?f=%5Cfrac%7By%27%7D%7Bx%7D%3D%5Cfrac%7B10%7D%7B6279%7D)
Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279
Answer: 17.5 gallons
Step-by-step explanation:
The formula to solve this question will be: g = d/m
where, g = number of gallons of gasoline used
d = distance travelled = 315 miles
m = miles per gallon = 18 miles/gallon
Therefore, the number of gallons of gasoline that Darnell will need to travel 315 miles will be:
g = d/m
g = 315/18
= 17.5 gallons