Find the domain and range of the function graphed below, in interval notation. Domain and range
1 answer:
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Answer:
Option C) 0.2358
Step-by-step explanation:
We are given the following data set:
0.23105, 0.4725, 0.8765, 0.4865, 0.5326, 0.7976
Formula:
where are data points,
is the mean and n is the number of observations.
Sum of squares of differences = 0.1122752556 + 0.008765640625 + 0.09633264063 + 0.006340140625 + 0.001123925625 + 0.05358067562 = 0.2784182787
Thus, the standard deviation for given data is
Option C) 0.2358
Answer:
Where 0 < x < 3
The location of the local minimum, is (2, 0)
The location of the local maximum is at (0, 16)
Step-by-step explanation:
The given function is f(x) = (x + 2)⁴
The range of the minimum = 0 < x < 3
At a local minimum/maximum values, we have;
∴ (-x + 2)³ = 0
x = 2
When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2
We have, f(2) = (-2 + 2)⁴ = 0
The location of the local minimum, is (2, 0)
Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3
When x = 0, -x + 2 = 0 + 2 = 2
Similarly, we have;
-x + 2 = 1, when x = 1
-x + 2 = 0, when x = 2
-x + 2 = -1, when x = 3
Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16
The location of the local maximum is at (0, 16).